Since PQ bisects CX at point J, JX=CJ
4y=y+9
-y -y
3y=9
divide by 3
y=3
Answer:
1680 kwhr
Step-by-step explanation:
See attached for explanation. I converted watt*hr to kW*hr by dividing by 1000.
Fans Bulbs
40 100
50 60 W
10 6 hours/day
20000 36000 W*hr/day
30 30 days/month
600000 1080000 W*hr/month
600 1080 kWhr/month
Total = 1680 kWhr/month
tan(40) = (y + 1.5) / (x + 20)
y + 1.5 = (x + 20)[tan(40)]
y = (x + 20)[tan(40)] - 1.5
tan(60) = (y + 1.5) / x
y + 1.5 = (x)[tan(60)]
y = (x)[tan(60)] - 1.5
(x)[tan(60)] - 1.5 = (x + 20)[tan(40)] - 1.5
(x)[tan(60)] = (x + 20)[tan(40)]
(x)[tan(60)] = (x)[tan(40)] + (20)[tan(40)]
(x)[tan(60)] - (x)[tan(40)] = (20)[tan(40)]
(x)[tan(60) - tan(40)] = (20)[tan(40)]
x = [(20)(tan(40))] / [tan(60) - tan(40)]
x = 18.8 meters
So first you would go 1+y=1 and the go 1+0=1
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The probability of passing the test is 
The sample size is n = 10
Generally the distribution of the comprehensive testing of equipment follows a binomial distribution
i.e

and the probability distribution function for binomial distribution is

Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as

=> ![P(X \ge 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}] + [^{10}C_{10} * (0.95)^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%20%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%280.95%29%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \ge 9) = [0.3151] + [0.5987]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B0.3151%5D%20%2B%20%5B0.5987%5D%20)
=> 