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Amanda [17]
3 years ago
5

8)An unprepared student makes random guesses for the ten true-false questions on a quiz. Find the probabilitythat there is at le

ast one correct answer.A)0.100B)0.900C)0.001D)0.999
Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

D.) 0.9990

Step-by-step explanation:

Given :

Number of questions = 10

True or False questions ; probability of success, p = 1/2 = 0.5

Using binomial distribution :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

Probability of getting atleast one correct answer :

P(x ≥ 1) = p(1) + p(2) +... P(x = 10)

Using a binomial probability calculator :

P(x ≥ 1) = 0.9990

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nydimaria [60]
 2x - 48 >= 4
2x >= 52
  x >= 26

answer is D. x >= 26

4 0
3 years ago
An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be
VLD [36.1K]
I don't like trying all of them so I will make up my own which will probably be in the answers 
so equation is
f(x)=pay
x=hours worked
solve so 
f(1)=110
f(2)=130
f(3)=150
f(4)=170

they seem to be increasing in 20 increments so therefor the pay is linked to hours times 20 so that measn that every hour he works, he gets 20 dollars
therefor the answer is f(n+1)=f(n)+20 since we know that 1 hour=$20 so n+1hour=n+$20

the answe ris f(n+1)=f(n)+20

5 0
3 years ago
Read 2 more answers
The output is the cube of the input
MakcuM [25]
The output is the cute of the input is written as y = x³.
5 0
3 years ago
Help if you can do this please
olga nikolaevna [1]

Answer:

Step-by-step explanation:

a. Since the parabola is compressed by a factor of 1/3 we can state:

  • a parabola is written this way : y=(x-h)²+k
  • h stands for the translation to the left ⇒ 2*3=6
  • k for the units down  ⇒4*3=12

So the equation is : y=(x-6)²+12

b.Here the parabola is stretched by a factor of 2 so we must multiply by 1/2

  • We khow that a parabola is written this way : y=(x-h)²+k
  • (h,k) are the coordinates of the vertex
  • the maximum value is  7*0.5=3.5
  • we khow tha the derivative of a quadratic function is null in the maximum value
  • so let's derivate (x-h)²+k= x²+h²-2xh+k
  • f'(x)= 2x-2h    h is 1 since the axe of simmetry is x=1
  • f'(x)=2x-2 ⇒2x-2=0⇒ x= 1
  • Now we khow that 1 is the point where the derivative is null
  • f(1)=3.5
  • 3.5=(x-1)²+k
  • 3.5= (1-1)²+k⇒ k=3.5

So the equation is : y=(x-1)²+3.5

7.

the maximum height is where the derivative equals 0

  • h= -5.25(t-4)²+86
  • h= -5.25(t²-8t+16)+86
  • h=-5.25t²+42t-84+86
  • h=-5.25t²+42t+2

Let's derivate it :

  • f(x)= -10.5t+42
  • -10.5t+42=0
  • 42=10.5t
  • t= 42/10.5=4

When the height was at max t=4s

  • h(max)= -5.25(4-4)²+86 = 86 m

h was 86m

8 0
3 years ago
30/10 as a whole number
mrs_skeptik [129]
3.

30 divided by 10 equals 3
7 0
3 years ago
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