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2 years ago

1. give each solid a geometric name. be as precise as you canаbс

Mathematics

1 answer:

UkoKoshka [18]2 years ago

7 0

The examples of geometric names include triangle, circle, square, rectangle, pentagon, etc.

<h3>What is a geometric name?</h3>

Your information is incomplete as the shapes aren't given. Therefore, an overview will be given.

A geometric name is the name that is given to a shape. In this case, examples include triangle, circle, square, rectangle, pentagon, etc.

Triangle has three sides. A square has four equal sides. A rectangle has opposite sides equal, etc

Learn more about geometric on:

brainly.com/question/16982223

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Find the zeros of each function by using a graph and a table. f(x)=x^2+2x–24.

Alborosie

Explanation

Step 1

$f(x)=x^2+2x-24$

Zeros

A(-6,0) B(4,0)

because

$\begin{gathered} f(x)=x^2+2x-24 \\ f(-6)=(-6)^2+2(-6)-24=36-12-24=0 \\ f(4)=4^2+2\cdot4-24=16+8-24=0 \end{gathered}$

Step 2

table

$\begin{gathered} (-6,0) \\ (4,0) \\ f(-1)=-1^2+2\cdot-1-24=1-2-24=-25 \\ (1,-25) \\ \end{gathered}$

I hope this helps you

5 0

1 year ago

Please help me with algebra!<br> Don't answer if you don't know how to do it.

astra-53 [7]

This is all a bit complicated so try and stick with me on this one!

This one is the first problem in the first picture! a + 2 / a^2 + a - 1 / a + 1/ -a^2 - 2a - 1

= a^4 + a^3 - a^2 - a / -a^5 - 3a^4 - 3a^3 - a^2

= -a^3 - a^2 + a + 1 / a^4 + 3a^3 + 3a^2 + a

= -a^3 - a^2 + a + 1/ a^4 + 3a^3 + 3a^2 + a

= (-a - 1) (a + 1) (a - 1) / a(a+ 1) (a + 1) (a + 1)

= -a + 1 / a^2 + a

The second problem in the first picture! 3x / y + 3x - y^2 / 3xy - 9x^2 + y^2 + 9x^2 / y^2 - 9x^2

= -81x^4y + 18x^2y^3 - y^5 / 243x^5 - 54x^3y^2 + 3xy^4

This one is for the last picture! 4y^2 + 4y + 1 / 4y - 8y^2 - 4y^2 + 1 / 4y + y

= 16y^3 + 24y^2 / -32y^3 + 16u^2

= 16y + 24 / -32y + 16

= 2y + 3 / -4y + 2

I hope this was helpful!!!

Please remember to rate/thank/mark as brainliest if you see fit! (:

3 0

3 years ago

Can anyone help me out ?

KengaRu [80]

She made her first mistake in step 2

-2x+5 =-11

add 5 to each side

-2x-5+5 = -11+5

-2x = -6 (not -16)

divide by -2

-2x/-2 = -6/-2

x = 3

She added 5 to 11 and got 16 and made it negative instead of subtracting 5 from 11 and making it negative

6 0

3 years ago

Read 2 more answers

Hi, Can someone please help me with this question, THANKS

kherson [118]

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6 0

3 years ago

If the foci of an ellipse are (negative 5 comma 2 )and (7 comma 2 ), then what are the coordinates of the center of the ellips

8090 [49]

Answer:(1,2)

Step-by-step explanation:

Given

Focii of an Ellipse are (-5,2) and (7,2)

As the y co-ordinate is same therefore it is a horizontal Ellipse

and we know that center of the Ellipse is the midpoint of two Focii

x co-ordinate of center is $x=\frac{-5+7}{2}=\frac{2}{2}=1$

Y co-ordinate of center is $y=\frac{2+2}{2}=2$

Therefore co-ordinates of center is (1,2)

4 0

2 years ago