Answer:
The linear equation for Shana's elevation is 
.
Step-by-step explanation:
According to the statement, we find that Shana is climbing at constant rate in time and height as a function of time can be represented by linear function:
(Eq. 1)
Where:
- Initial height above sea level, measured in feet.
- Elevation above sea level, measured in feet.
- Climbing rate, measured in feet per minute.
- Time, measured in minutes.
If we know that 
, 
and 
. the initial height above sea level is:
The linear equation for Shana's elevation is .
Answer:
-125w^6z^24
Step-by-step explanation:
I believe it would be (if x was the number):
x - 5 ≥ -28. Hope this helps!
The answer is 12y^2 + 2y - 5
The solution:
(72y^3 + 12y^2 - 30y) / 6y =
(6y)*(12y^2 + 2y - 5) / 6y = 12y^2 + 2y - 5
(x-4)(x-4)
5(x^2-8x+16)=60
5x^2-40x+80=60
5x^2-40x+20=0
5(x^2-8x+4)
something like this
