All categories

2 years ago

Express the polynomial z^2-z^4+2z^2 in standard form and then classify it.

2 answers:

8 0

Write this as -z⁴+3z²=-z²(z²-3). This is a quadratic in z². It could also be called a quadratic quartic.
As a polynomial it is fourth degree.

liubo4ka [24]2 years ago

4 0

Answer:

342^1

Step-by-step explanation:

changes in roman military armor and training techniques

You might be interested in

Show that √(1-cos A/1+cos A) =cosec A - cot A

Gennadij [26K]

Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

$1/sinA = cscA\\\\cosA/sinA = cotA$

Simplify:

$\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}$

5 0

2 years ago

Evaluate x square2 +12,when x=3

GarryVolchara [31]

Answer:

Step-by-step explanation:

3^2=9

9+12=21

Keep it up

6 0

2 years ago

A publisher displays its latest magizine on its website

IceJOKER [234]

We need to know about unitary method to solve the problem. The length of the actual magazine cover is 8 inches, the width of the actual magazine cover is 11 inches, the length of the new magazine cover is 32cm and the width of the new magazine cover is 44cm.

Unitary method is used to find the value of a unit object. . In this question we know the scale is 6cm to 1 inch for actual magazine cover, the length is given to be 48 cm and the width is 66cm,

length of actual magazine cover= 48/6=8 inches

width of actual magazine cover= 66/6=11 inches

The new scale is 4 cm to 1 inch

length of new magazine cover=8x4=32 cm

width of new magazine cover =11x4=44 cm

Therefore the length of the actual magazine cover is 8 inches, the width of the actual magazine cover is 11 inches, the length of the new magazine cover is 32 cm and the width of the new magazine cover is 44cm.

Learn more about unitary method here:

brainly.com/question/22056199

#SPJ1

Your question was incomplete. Please refer below for the entire question.

A publisher displays its latest magazine cover on its website.

The publisher scales up the front cover of the magazine using a scale of 6 centimeters to 1 inch. The length of the scale drawing is 48 centimeters, and its width is 66 centimeters.

The length of the actual magazine cover is inches.

The width of the actual magazine cover is inches.

The scale drawing is too big to view on a computer screen without scrolling.

the publisher uses a new scale of 4 centimeters to 1 inch.

The length of the new scale drawing is centimeters.

The width of the new scale drawing is centimeters.

7 0

1 year ago

What are 2 ways to solve the problem 9×1×5 = ?

aliina [53]

2ways you can solve that is by multiplying 9 by 1 then by 5 or 9by 5 then by 1

6 0

2 years ago

The record high temperature in Alabama is 112°F and the record low temperature is −27°F. What is the difference between the high

Minchanka [31]

The difference between the highest and lowest temperature is 85°F.

7 0

2 years ago

Read 2 more answers