Note: I'm assuming that your teacher wants you to use the approximation pi = 3.14
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Problem 1)
Plug the value r = 4.5 into the formula below to find the approximate volume
V = (4/3)*pi*r^3
V = (4/3)*pi*(4.5)^3
V = (4/3)*pi*91.125
V = (4/3)*91.125*pi
V = 121.5*pi
V = 121.5*(3.14)
V = 381.51
So the approximate volume of this sphere is roughly 381.51 cubic cm
Note: we can write "cubic cm" as "cm^3"
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Problem 2)
The formula to use for the volume of a cylinder is
V = pi*r^2*h
where r is the radius and h is the height
In this case, we have r = 2.1 and h = 8.0
V = pi*r^2*h
V = pi*(2.1)^2*8.0
V = pi*4.41*8.0
V = pi*35.28
V = 35.28*pi
V = 35.28*(3.14)
V = 110.7792
The volume is roughly 110.7792 cubic cm
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Problem 3)
Now we use the formula
V = (1/3)*pi*r^2*h
which is the volume of a cone. Note how this is simply 1/3 the volume of the cylinder (with same radius and height)
Use r = 8.0 and h = 2.0
V = (1/3)*pi*r^2*h
V = (1/3)*pi*(8.0)^2*(2.0)
V = (1/3)*pi*64*2
V = (1/3)*pi*128
V = (1/3)*128*pi
V = (128/3)*pi
V = (128/3)*(3.14)
V = 133.973333
The approximate volume is 133.973333 cubic cm
Answer:
3361713882 this is the correct answer
Step-by-step explanation:
I hope it helps you
Wow, i wonder why they were lifting a large boulder? They should put it down they could get hurt!!
Answer:
7/4!
Step-by-step explanation:
I think?
Answer:
(9, 6)
Step-by-step explanation:
<u>Midpoint formula is:</u>
- x = (x₁ + x₂)/2
- y = (y₁ + y₂)/2
<u>Having coordinates of one end- and midpoint </u>(-5, 12) <u>and</u> (2, 9)<u>:</u>
- x₁ = -5, y₁ = 12
- x = 2, y = 9
<u>we get the coordinates of the missing endpoint with coordinates</u> (x₂, y₂):
- x₂ = 2x - x₁ = 2*2 - (-5) = 4 + 5 = 9
- y₂ = 2y - y₁ = 2*9 - 12 = 18 - 12 = 6
<u>So the missing point is</u>: (9, 6)
