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Natali [406]
3 years ago
9

Solve for x please 1/6x=10

Mathematics
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

x=60

Step-by-step explanation:

1/6x=10

multiply both sides by 6 to get x

x=60

bekas [8.4K]3 years ago
3 0

Answer:

x=60

Step-by-step explanation:

In order to solve for x, we must isolate x on one side of the equation.

The equation given is:

\frac{1}{6}x=10

1/6 and x are being multiplied. The inverse of multiplication is division. Divide both sides of the equation by 1/6

\frac{1}{6}x/\frac{1}{6}=10/\frac{1}{6}

When dividing by a fraction, you can multiply by the reciprocal of the fraction instead.

To find the reciprocal, flip the numerator and denominator.

1/6 ⇒ flip top number and bottom number ⇒ 6/1=6

Replace the division by 1/6 with multiplication by 6.

\frac{1}{6}x * 6=10*6

x= 10 *6

x=60

The solution to this equation is x=60

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Amy invested $5,600 in a CD that pays eight percent compounded quarterly. How many years will it take before the CD is worth 8,2
harina [27]

Answer:

It will take 4.858 years before the CD worth 8228.24

Step-by-step explanation:

* Lets revise the compound interest

- The formula for compound interest, including principal sum, is:

  A = P (1 + r/n)^(nt)

- Where:

• A = the future value of the investment/loan, including interest

• P = the principal investment amount (the initial deposit or loan amount)

• r = the annual interest rate (decimal)

• n = the number of times that interest is compounded per unit t

• t = the time the money is invested or borrowed for

- To find the time you can use the formula

  t = ln(A/P) / n[ln(1 + r/n)]

* Lets solve the problem

∵ P = $5600

∵ A = 8228.24

∵ r = 8/100 = 0.08

∵ n = 4

- Substitute all of these values in the equation of t

∴ t = ln(8228.24/5600) / 4[ln(1 + 0.08/4)] = 4.858 years

* It will take 4.858 years before the CD worth 8228.24

6 0
4 years ago
A bank gives you a simple interest loan at a rate of 5.5% . After 3 years you have paid the entire principal plus $41.91 in inte
Tomtit [17]
It will equate to about $35.97 if you wish to check the math you take 35.97 multiply it by 5.5% getting 1.97835 or 5.93505 for the whole three years add it to 35.97 and get 41.90505
7 0
4 years ago
If y varies directly with x and y is -6 when x is 2, what is x when y is -22?
zubka84 [21]

Answer:

x = \frac{22}{3}

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = - 6 when x = 2, then

- 6 = 2k ( divide both sides by 2 )

- 3 = k

y = - 3x ← equation of variation

When y = - 22, then

- 22 = - 3x ( divide both sides by - 3 )

x = \frac{-22}{-3} = \frac{22}{3}

8 0
3 years ago
Rita is hiking along a trail that is 13.7 miles long. So far she has hiked along one-tenth of the trail. How far has Rita hiked?
Rus_ich [418]
1.37 miles because 13.7 times 0.1 is 1.37.
6 0
3 years ago
The 2004 presidential election exit polls from the critical state of Ohio provided the following results. There were 2020 respon
lord [1]

Answer: a)  0.490\leq p\leq0.582

b)  0.501\leq p

Step-by-step explanation:

Given : Sample size of respondents in the exit polls  : n= 2020

Number of respondents voted for George Bush = 412

Sample proportion: \hat{p}=\dfrac{412}{768}\approx0.536

a) Critical value for 99% confidence level : z_{\alpha/2}=2.576

Confidence interval for proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

=0.536\pm (2.576)\sqrt{\dfrac{0.536(1-0.536)}{768}}\\\\=0.536\pm0.046\\\\=(0.490,\ 0.582)

Hence, the 99% confidence interval for the proportion of college graduates in Ohio that voted for George Bush: 0.490\leq p\leq0.582

b) Critical value for 95% confidence level : z_{\alpha/2}=1.96

Lower confidence bound for the proportion :

\hat{p}- z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.536-(1.96)\sqrt{\dfrac{0.536(1-0.536)}{768}}\\\\=0.536-0.035=0.501

Hence,  a 95% lower confidence bound for the proportion of college graduates in Ohio that voted for George Bush : 0.501\leq p

7 0
3 years ago
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