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belka [17]
3 years ago
7

Clem Colfax had $10 to buy groceries. He needed milk costing 70 cents a carton, bread costing 60 cents a loaf, breakfast cereal

costing 50 cents a box, and meat costing $1.50 a pound. He bought twice as many cartons of milk as he did loaves of bread, the number of boxes of cereal was one more than the number of loaves of bread, and the number of pounds of meat was the same as the number of boxes of cereal. How many of each did he buy if the total he spent was exactly $10?
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
The first thing we must do for this case is to define variables:
 w: pounds of meat
 x: carton of milk
 y: loaf of bread
 z: cereal breakfast box
 We write the system of equations:
 0.70x + 0.60y + 0.50z + 1.50w = 10
 x = 2y
 z = y + 1
 w = z
 Solving the system we have:
 w = 3
 x = 4
 y = 2
 z = 3
 Answer:
 
3 pounds of meat
 
4 cartons of milk
 
2 loaves of bread
 
3 boxes of breakfast cereal
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A sequence of Bernoulli trials consists of choosing components at random from a batch of components. A selected component is eit
Drupady [299]

Answer:

a) 0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

Step-by-step explanation:

A sequence of Bernoulli trials composes the binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a selected component is non-defective is 0.8

This means that p = 0.8

a) Three non-defective components in a batch of seven components.

This is P(X = 3) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{7,3}.(0.8)^{3}.(0.2)^{4} = 0.0287

0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 8 non-defective components are drawn before the first defective component is chosen.

Now the order is important, so the we just multiply the probabilities.

8 non-defective, each with probability 0.8, and then a defective, with probability 0.2. So

p = (0.8)^8*0.2 = 0.0336

0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

4 0
3 years ago
Show all work to identify the asymptotes and state the end behavior of the function f(x)=5x/x-25
Nina [5.8K]

Using the asymptote concept, it is found that:

  • The vertical asymptote is of x = 25.
  • The horizontal asymptote is of y = 5.
  • Considering the horizontal asymptote, it is found that the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

f(x) = \frac{5x}{x - 25}

Considering the denominator, the vertical asymptote is:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5

Hence the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

More can be learned about asymptotes and end behavior at brainly.com/question/28037814

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6 0
2 years ago
Why are asymptotes important in rational function graphs
leonid [27]

Answer:

when sketching the curves of functions.

Step-by-step explanation:

There is a wide range of graph that contain asymptotes and that includes rational functions, hyperbolic functions, tangent curves, and more. Asymptotes are important guides when sketching the curves of functions. This is why it’s important that we know the properties, general forms, and graphs of each of these asymptotes.

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