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3 years ago

Lian has $1.00 She has only nickels and dimes. Lian has twice as many dimes as nickels How many dimes does she have?

Mathematics

1 answer:

tangare [24]3 years ago

3 0

Answer: B) 8

Step-by-step explanation:

Because she has twice as many dime as nickels, that automatically makes 5, 3, and 7 invalid answers since you cannot have whole halfs of them.

8 dimes = 80 c.

8/2 = 4

4 nickles = 20 c.

80c + 20c = $1.00

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observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3

agasfer [191]

Answer:

The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"

Step-by-step explanation:

Given values:

$2xy =6.....(a)\\\\x-y= 3.....(b)\\\\$

After solve equation (a) we get

$\ equation: \\\\2xy= 6\\\\xy =\frac{6}{2} \\\\xy = 3.....(x)\\\\$

After solve equation (b) we get

$\ equation: \\\\x-y =3\\\\x= 3+y....(x1)\\$

put the value of x in to equation (x)

$(3+y)y = 3\\$

$y^2+3y-3=0\\\\\ compare \ the \ value \ with \ ay^2+by+c=0\\a= 1\\b=3\\c=-3\\\ Formula: \\y= \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\y= \frac{-3\pm \sqrt{9+12}}{2}\\y= \frac{-3\pm \sqrt{21}}{2}\\$

The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29

5 0

3 years ago

The number 424 is what percent of 530

postnew [5]

424/530=0,8
0,8*100%=80%

5 0

3 years ago

Read 2 more answers

Step 1: Place the graph paper in landscape orientation. Measure from the top left hand corner 6 inches right and 5 inches down.

cluponka [151]

<h3>How to determine the hypotenuse?</h3>

Step 1 and 2: Draw an isosceles right triangle

See attachment (figure 1) for this triangle

The legs of this triangle have a length of 1 inch

Step 3: The hypotenuse

This is calculated using the following Pythagoras theorem

$h^2 = 1^2 + 1^2$

This gives

$h = \sqrt 2$

Step 4: Draw another isosceles right triangle

Add 1 inch to one of the legs

See attachment (figure 2) for this triangle

The legs of this triangle have lengths of 1 inch and 2 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

$h^2 = 2^2 + 1^2$

This gives

$h = \sqrt 5$

Step 5: Draw another isosceles right triangle

Add 1 inch to one of the legs

See attachment (figure 3) for this triangle

The legs of this triangle have lengths of 1 inch and 3 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

$h^2 = 3^2 + 1^2$

This gives

$h = \sqrt {10$

Step 6: Draw another isosceles right triangle

Add 1 inch to one of the legs

See attachment (figure 4) for this triangle

The legs of this triangle have lengths of 1 inch and 4 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

$h^2 = 4^2 + 1^2$

This gives

$h = \sqrt{[17$

See that the hypotenuse is the square root of 17

Hence, the right triangle whose legs are 1 inch and 4 inches has an hypotenuse of √17

Read more about right triangles at:

brainly.com/question/2437195

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8 0

2 years ago

Help me please I need help and its due soon

marshall27 [118]

Answer:

1/2 4 ( I believe it's the correct answer, forgive me if I'm wrong)

4 0

3 years ago

Dos hombres pueden hacer un trabajo en 12 días trabajando juntos. Si a B le toma 10 días más que a A hacer el trabajo solo, dete

pychu [463]

Responder:

El tiempo que toma A para completar el trabajo solo es de 20 días.

Explicación paso a paso:

datos proporcionados:

Tiempo que tarda (A + B) en terminar el trabajo = 12 days.

Deje que A A le tome tiempo completar el trabajo solo = x

entonces el tiempo que B tomó para completar el trabajo solo = x+10

1 día de trabajo de A + B = $\frac{1}{12}$

1 día de trabajo de A = $\frac{1}{x}$

1 día de trabajo de B = $\frac{1}{x+10}$

1 día de trabajo de A = {(

1 día de trabajo de A + B} - {1 día de trabajo de B}

$\frac{1}{x} =((\frac{1}{12})-(\frac{1}{x+10}))$

Resolviendo la ecuación que obtenemos.

$\frac{1}{x} =((\frac{x+10}{12(x+10)})-(\frac{1\times12}{12(x+10)}))$

$\frac{1}{x} =(\frac{x+10-12}{12x+120})$

$\frac{1}{x} =(\frac{x-2}{12x+120})$

$12x+120=x(x-2)$

$12x+120=x^2-2x$

$x^2-2x-12x-120=0$

$x^2-14x-120=0$

$x^2+6x-20x-120=0$

$x(x-6)-20(x-6)=0$

$(x-20)(x+6)=0$

Ahora resolviendo 2 valores de x obtenemos

$x-20=0\\x=20$

$x+6 =0\\x =-6$

El número de días no puede ser negativo, por lo tanto, x = -6 no es válido

por lo tanto, el número de días que A puede completar el trabajo solo es de 20 días

3 0

3 years ago