Answer:
1) x=1; x= 0 is an extraneous solution
Step-by-step explanation:
5 = 4x + 1
5 = 4 x 1 + 1
5 = 5
x = 1
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x x^2
0 x 0^2
0 x 0 = 0
x = 0
:)
Y = kx
k = y/x
k = 2/12
k = 1/6
so when x = 12
y = kx
y = 1/6(5)
y = 5/6
answer
when x = 5 y = 5/6
Answer:
C
Step-by-step explanation:
denominator is different from zero so that

