Answer:
Margin of error = 4.21 ounces
Step-by-step explanation:
According to the Question,
- Given That, You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8 ounces
Therefore, Sample mean = 31 ounces , Sample size(n) = 25 , Alpha(α) = 0.10 & Population standard deviation(σ) = 12.8 ounces
- Thus, Margin of error = × σ / √n ( at α=.010 is 1.645)
Putting The Values, We get
1.645 × (12.8 / √25 ) ⇒ 4.2112 ≈ 4.21
Thus, the maximum margin of error associated with a 90% confidence interval for the true population mean turtle weight is 4.21 ounces
Answer:
10 cm
Step-by-step explanation:
From the diagram,
Applying,
lw = 5/2(bh)..................... Equation 1
Where l = length of the rectangle, w = width of the rectangle, b = base of the triangle, h = height of the triangle.
make w the subject of the equation
w = 5(bh)/2l............... Equation 2
From the diagram,
Given: l = 12 cm, b = 6 cm, h = 8 cm
Substitute into equation 2
w = 5(6×8)/(2×12)
w = 10 cm
Hence the width of the rectangle is 10 cm
Answer:
A
Step-by-step explanation:
90-49=41
41-3=38
49+(38+3)=90
You would just have to isolate for x
so it would simply become
-1.56/-7.8
= 0.2