Answer: the efficiency of the first car is 25 miles per gallon.
the efficiency of the second car is 30 miles per gallon.
Step-by-step explanation:
Let x represent the efficiency of the first car.
Let y represent the efficiency of the second car.
Distance = car efficiency × number of gallons.
The first car consume 25 gallons of gas and the second consumed 15 gallons of gas. The two cars Drove a combined total of 1075 miles. It means that
25x + 15y = 1075- - - - - - - - - - -1
The sum of the fuel efficiencies was 55 miles per gallon. It means that
x + y = 55
Substituting x = 55 - y into equation 1, it becomes
25(55 - y) + 15y = 1075
1375 - 25y + 15y = 1075
- 25y + 15y = 1075 - 1375
- 10y = - 300
y = - 300/-10
y = 30
x = 55 - y = 55 - 30
x = 25
The answer would be 42
42*3 = 126
126+5 = 131
3(n)+5=131
3(n)+5 -5= 131-5
3(n)=126
3(n)/3= 126/3
n= 42
Answer:
The answer is 3, 6.
Step-by-step explanation:
The numbers in the top rows on the left side of the equation is 1, 4 and 2, 2.
1, 4 + 1, 2 = (1 + 2), (4 + 2) = 3, 6
Answer:
163%
Step-by-step explanation:
Find in-between 25 and 300, which is 162.5 ,round to the nearest percentage being 163%. Hence your answer
Answer:
m ≥ 0
Step-by-step explanation:
Since the cost is represented by c = 0.12m, the domain should be a positive number, this is because number of minutes can't be written in negative. Therefore, the most reasonable number for the domain would be the set of positive whole numbers which means, m≥0.
