If you would like to find a factor of 6x^2y + 8x^2 - 30y - 40, you can calculate this using the following steps:
<span>6x^2y + 8x^2 - 30y - 40 = 2x^2 * (3y + 4) - 10 * (3y + 4) = (3y + 4) * (2x^2 - 10) = 2 * (3y + 4) * (x^2 - 5)
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The correct result would be 3y + 4.
Answer:
The differential equation will be like the one shown below
Step-by-step explanation:
Data:
Let the equation be given as:
y(4) + 8y' = 6
The equation will be expressed linearly as follows:
y(4) + 8

This is the linear form of the differential equation.
Answer:
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Step-by-step explanation:
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