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tankabanditka [31]
3 years ago
13

Ramon wants to make an acute triangle with three pieces of wood. So far, he has cut wood lengths of 7 inches and 3 inches. He st

ill needs to cut the longest side. What length must the longest side be in order for the triangle to be acute?
Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

Answer:

less than StartRoot 58 EndRoot inches but greater than 7 inches

         or

C

Step-by-step explanation:

Honestly just did it on edg, good luck. : D

Anna35 [415]3 years ago
3 0

Answer:

7.6 inches to make an acute triangle

Step-by-step explanation:

a^2+b^2=c^2

7^2+3^2=c^2

49+9=c^2

58=c^2

Square root both sides

c=7.6 inches

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Step-by-step explanation:

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3 years ago
How do you calculate a net worth statement?
marissa [1.9K]

Answer:

a. Assets - Liabilities

Step-by-step explanation:

Assets/Liabilities is a management method to minimize risk. So, it cannot be the answer.

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8 0
3 years ago
Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?
cluponka [151]

Under the given transformation, the Jacobian and its determinant are

\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2

so that

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv

where D' is the region D transformed into the u-v plane. The remaining integral is the twice the area of D'.

Now, the integral over D is

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y

but through the given transformation, the boundary of D' is the set of equations,

\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}

We require that u>0, and the last equation tells us that we would also need v>0. This means 1\le v\le\sqrt2 and 0, so that the integral over D' is

\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6

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2 years ago
1. The exact value of cos60
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3 years ago
Maryam's rectangular bedroom is 9 feet by 12 feet. What is the diagonal distance from one corner to the opposite corner?
ra1l [238]
Create a right triangle with the the two legs being sides of 9 and 12...then use the Pythagorean theorem to solve

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Square root both sides to get c = 15 feet.
4 0
2 years ago
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