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3 years ago

Find the product of (3.7 × 104) and 2.

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

7 0

(3.7 x 104)2 = 769.6
In Scientific notation:
7.696 x 10^2

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What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?

Darya [45]

Answer:

$4 \sqrt{2} i$

Step-by-step explanation:

We want to find the sum of

$\sqrt{ - 2} + \sqrt{ - 18}$

We can rewrite this as

$\sqrt{ 2 \times - 1} + \sqrt{ 18 \times - 1}$

This becomes;

$\sqrt{2} \times \sqrt{ - 1} + \sqrt{18} \times \sqrt{ - 1}$

Recall that;

$i = \sqrt{ - 1}$

This implies that;

$\sqrt{2} i + 3 \sqrt{2} i$

Combine like terms:

$4 \sqrt{2} i$

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3 years ago

A positive number with an absolute value less than 5.

Goryan [66]

Answer:

3 I think.

Step-by-step explanation:

it's positive and it's also an absolute

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2 years ago

Equation of a line that passes through (2,-3) with the slope of 1/2

Irina18 [472]

In point slope form:
y+3=1/2(x-2)

In slope intercept
y= 1/2x-4

7 0

2 years ago

Read 2 more answers

I will give brainiest if correct

Natalka [10]

Its C. Add 3 and 15 which gives you 18. Then move the variable (4x) to the left. Then combine like terms which are the x’s and you should get 3x. Then divide both sides by 3. (18/3 = 6)

5 0

2 years ago

At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 111 keypads is analyzed. Find

Serggg [28]

Answer:

The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

Let p = the proportion of keypads that pass inspection at a cell phone assembly plant.

The probability that a randomly selected cell phone keypad passes the inspection is, p = 0.77.

A random sample of n = 111 keypads is analyzed.

Then the sampling distribution of $\hat p$ is:

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})\\\Rightarrow \hat p\sim N (0.77, 0.04)$

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:

$P(0.72$

$=P(-1.25$

Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

8 0

3 years ago