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4 years ago

Describe the Kuiper belt including its location, composition and relationship to dwarf planets

Chemistry

1 answer:

goldenfox [79]4 years ago

8 0

<h3>Kupier Belt:</h3>

Location:

Kuiper belt also known as Edgeworth-Kuiper belt which is in the shape of "flat ring of icy small bodies" that revolve around the Sun beyond the orbit of the planet Neptune. It is a "circumstellar disc" that is similar to the "asteroid belt" in the outer solar system.

Composition: 

Its composition mainly consists of "small bodies or remnants" from the time when the solar system was formed. It also consists of frozen volatiles (termed "ices"), such as "methane, ammonia, and water".

Relationship to dwarf planets:

This belt is also a home to the dwarf planets such as "Pluto, Haumea, and Makemake".

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During a titration, 40.0 ml of 0.25M NaOH were required to neutralize 50.0ml of HCl. What's the concentration of the HCl solutio

Stolb23 [73]

Answer:

Explanation:

M1V1 = M2V2

40.0ml*0.25M = M2*50.0ml

M2 = 40.0*0.25/50.0 = 0.20 M

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3 years ago

At the end of the isomerization reaction, what chemical is used to quench the residual bromine?

bazaltina [42]

Answer:

They are constitutional isomers and diastereomers.

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3 years ago

the atomic mass of chlorine is 35.45 u. Is it possible for any single atom of chlorine to have a mass number of exactly 35.45? E

KonstantinChe [14]

No, this number is the result of the natural mixture of Cl-35 and Cl-37, which produces the observed value.

The mass of Cl on the periodic table is 35.45 atomic mass units. This is an average mass of the isotopes (different Cl atoms in nature). Most Cl atoms in nature have a relative mass of about 35 atomic mass units. Most of the remaining Cl isotopes have a relative mass of 37 atomic mass units.

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3 years ago

Answer pls ASAP will mark the brainliest

harina [27]

First one……………………………….

6 0

3 years ago

Read 2 more answers

) In the Deacon process for the manufacture of chlorine, HCl and O2 react to form Cl2 and H2O. Sufficient air (21 mole% O2, 79%

LiRa [457]

Answer:

Here's what I get.

Explanation:

1. Write the chemical equation

$\rm 4HCl + O$_{2} \longrightarrow \,$ 2Cl$_{2}$ + 2H$_{2}$O$

Assume that we start with 4 L of HCl

2. Calculate the theoretical volume of oxygen

$\text{V}_{\text{O}_{2}}= \text{4 L HCl} \times \dfrac{\text{1 L O}_{2}}{\text{4 L HCl}} = \text{1 L O}_{2}}$

3. Add 35% excess

$\text{V}_{\text{O}_{2}}= \text{1 L O}_{2}} \times 1.35 = \text{1.35 L O}_{2}}$

4. Calculate the theoretical volume of nitrogen

$\text{V}_{\text{N}_{2}} = \text{1.35 L O}_{2}} \times \dfrac{\text{79 L N}_{2}}{\text{21 L O}_{2}}} = \text{5.08 L N}_{2}}$

4. Calculate volumes of reactant used up

Only 85 % of the HCl is converted.

We can summarize the volumes in an ICE table

4HCl + O₂ + N₂ → 2Cl₂ + 2H₂O

I/L: 4 1.35 5.08 0 0

C/L: -0.85(4) -0.85(1) 0 +0.85(2) +0.85(2)

E/L: 0.60 0.50 5.08 1.70 1.70

5. Calculate the mole fractions of each gas in the product stream

Total volume = (0.60 + 0.50 + 5.08 + 1.70 + 1.70) L = 9.58 L

$\chi = \dfrac{\text{V}_{\text{component}}}{\text{V}_\text{total}} = \dfrac{\text{ V}_{\text{component}}}{\text{9.58}} = \text{0.1044V}_{\text{component}}\\\\\chi_{\text{HCl}} = 0.1044\times 0.60 = 0.063\\\\\chi_{\text{O}_{2}} = 0.1044\times 0.50 = 0.052\\\\\chi_{\text{N}_{2}} = 0.1044\times 5.08 = 0.530\\\\\chi_{\text{Cl}_{2}} = 0.1044\times 1.70 = 0.177\\\\\chi_{\text{H$_{2}${O}}} = 0.1044\times 1.70 = 0.177\\\\$

8 0

3 years ago