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stira [4]
2 years ago
14

How many moles are in 1.4 x 10^21 atoms of sodium?

Chemistry
1 answer:
Zepler [3.9K]2 years ago
3 0

Answer:

devide by avogadro constant 6.02*10^23

Explanation:

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Who discovered the flame test
Genrish500 [490]

Answer:

Thomas Melvill

Explanation:

...

6 0
3 years ago
If a chemical reaction catalyzed by an enzyme is being carried out, and there is a sudden, drastic decrease in temperature, what
LenaWriter [7]

If a chemical reaction catalyzed by an enzyme is being carried out, and there is a sudden, drastic decrease in temperature, the thing that will most likely to happen next is going to be the :

“enzyme activity will decrease, and the reaction will proceed very slowly, or possibly not at all.“

Explanation:

This compliance is required to how enzymes bind to other molecules and cause chemical reactions to occur on those molecules. Lowering the temperature reduces the motion of molecules and atoms, expecting this compliance is reduced or lost. As the temperature decreases, so do enzyme activity. While higher temperatures do increase the activity of enzymes and the rate of reactions,

5 0
2 years ago
Read 2 more answers
Using the periodic table, choose the more reactive metal. Ta or V Ta​
Jlenok [28]

Answer:

V Ta is more reactive, hope this helps!

8 0
2 years ago
What is the independent variable?<br> (For science)
DiKsa [7]

Answer:

The independent variable is what you change in the experiment.

Explanation:

The independent determines the dependent variable.

6 0
3 years ago
A 104 m3 thoroughly mixed pond has a water inflow and outflow of 5 m3/h. The inflow water contains 0.01 mol/m3 of chemical. Chem
Naily [24]

Answer:

C ≈ 1.44 × 10⁻³ mol/m³

Explanation:

The given information are;

The liquid volume the pond can hold = 104 m³

The volume of inflow into the pond = 5 m³/h

The volume of outflow into the pond = 5 m³/h

The concentration of the chemical in the inflow water = 0.01 mol/m³

The concentration of the chemical discharged directly into the water = 0.1 mol/h

The concentration, c_{(inflow)}, of chemical that enters the water through inflow per hour is given as follows;

c_{(inflow)} = 0.01 mol/m³ × 5 m³/h = 0.05 mol/h

The concentration, c_{(discharge)}, of chemical that enters the water through direct discharge per hour is given as follows;

c_{(discharge)} = 0.1 mol/h

The total concentration that enters the pond per hour is given as follows;

c_{(inflow)} + c_{(discharge)} = 0.1 mol/h + 0.05 mol/h = 0.15 mol/h

Whereby the water in the pond properly mixes with the pond, we have;

The concentration of chemicals (C) in the outflow water = 0.15 mol/(104 m³) ≈ 0.00144 mol/m³

C ≈ 1.44 × 10⁻³ mol/m³.

4 0
3 years ago
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