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3 years ago

11

During a titration, 40.0 ml of 0.25M NaOH were required to neutralize 50.0ml of HCl. What's the concentration of the HCl solutio

n? Question 6 options: A) 0.40M B) 0.10M C) 0.20M D) 0.25M

1 answer:

Stolb23 [73]3 years ago

7 0

Answer:

C)

Explanation:

M1V1 = M2V2

40.0ml*0.25M = M2*50.0ml

M2 = 40.0*0.25/50.0 = 0.20 M

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