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3 years ago

Rewrite the expression so that the GCF is factored completely: 2x^3y+18xy-10x^2y-90y

Mathematics

2 answers:

Agata [3.3K]3 years ago

6 0

2x^3y+18xy-10x^2y-90y

= 2xy(x^2 + 9)- 10y(x^2 + 9)

= (x^2 + 9)(2xy - 10y)

= (x^2 + 9) 2y(x - 5)

= 2y (x^2 + 9) (x - 5)

Gemiola [76]3 years ago

3 0

The final answer is:

= 2y (x^2 + 9) (x - 5)

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3 years ago

Population A and Population B both have a mean height of 70.0 inches with an SD of 6.0. A random sample of 50 people is picked f

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Answer:

Sample mean from population A has probably more accurate estimate of its population mean than the sample mean from population B.

Step-by-step explanation:

To yield a more accurate estimate of the population mean, margin of error should be minimized.

margin of error (ME) of the mean can be calculated using the formula

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z is the corresponding statistic in the given confidence level(z-score or t-score)

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for a given confidence level, and the same standard deviation, as the sample size increases, margin of error decreases.

Thus, random sample of 50 people from population A, has smaller margin of error than the sample of 20 people from population B.

Therefore, sample mean from population A has probably more accurate estimate of its population mean than the sample mean from population B.

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3 years ago

Use the quadratic formula to solve. Round to the nearest tenth if necessary. 2x^2 -3x -7 = 0

abruzzese [7]

The quadratic formula is:

$\frac{-b + \sqrt{b^2 - 4ac} }{2a}$ and $\frac{-b - \sqrt{b^2 - 4ac} }{2a}$

In this case, a = 2, b = -3, and c = -7

So, we can plug in the numbers to get:

$\frac{-(-3) + \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}$ and $\frac{-(-3) - \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}$

Simplifying, we get:

$\frac{3 + \sqrt{65} }{4}$ and $\frac{3 - \sqrt{65} }{4}$

You need to use a calculator to find what these would be in decimal form. The answer, rounded to the nearest tenth, is: x = 2.8, x = -1.3

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2 years ago