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guajiro [1.7K]
2 years ago
12

What is the least common factor for 5 and 6

Mathematics
2 answers:
notka56 [123]2 years ago
6 0

Answer:

The answer is 30

Step-by-step explanation:

RoseWind [281]2 years ago
4 0
The answer is 30 because 5 and 6 have no other common multiples.
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Find to numbers, A & B,whose Products, A x B, is less than the sum, A + B. Can you find to positive numbers?
NeTakaya

Answer:

any number, n, multiplied by 1 is less than n + 1, so A = 1, B = any number

For example, 1 % 7. 1 * 7 = 7. 1 + 7 = 8

Also, having one of the variables be a decimal can make the numbers smaller.

For example, 28 * 0.5 = 14. 28 + 0.5 = 28.5

8 0
3 years ago
What is the value of 4p-2 when p=8
3241004551 [841]

Answer: Hence, the value of expression is 30 when p = 8.

Step-by-step explanation:

Since we have given that

4p-2

and we have p = 8.

So, we substitute the value of p in the above expression.

so, it becomes,

4(8)-2\\\\4\times 8-2\\\\=32-2\\\\=30

Hence, the value of expression is 30 when p = 8.

3 0
3 years ago
The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

5 0
3 years ago
Find the value of x.<br> 64<br> 56°
nikklg [1K]

Answer:

answer is 60

Step-by-step explanation:

180-(64+56)=180-120=60

5 0
2 years ago
The side of a square is 2 7/2 inches. Using the area formula A = s2, determine the area of the square.
o-na [289]
<span>the answer A=49 square inches</span>
3 0
2 years ago
Read 2 more answers
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