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nadezda [96]
3 years ago
14

Isabel bought a new jacket for $48 before tax. She paid 6.5% in sales tax. How much was the sales tax?

Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0
C) $3.12
$48*.065=$3.12
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In March Tom had -£165 in his bank account. In April he had -£156. In which month did he have the least amount of money in his a
Flura [38]
March = -165
April = -156

In march he is negative MORE money, meaning he has MORE money in April

This question is trying to confuse you, ussually the lowest number means less, but these numbers are negative, so the lowest number means more.
He has the least amount of money in March


5 0
3 years ago
Could you please help me!?
Alinara [238K]

Answer:

Answer: 42.5

Step-by-step explanation:

It says 1 inch equals 5 feet. So, every inch is on the map is an extra 5 feet in real space. So if you think about it, all this is is a simple multiplication problem.

Here is the math:

8.5 * 5 = 42.5

Think about it, for every inch there is on the map there is an extra 5 feet in real space. There is 8 inches, so we need 5 extra feet for each of those 8 inches. So what we get for 1 inch is 5 feet, for 2 inches 10 feet, 3 inches 15 feet, etc etc until we reach 8 inches. For the 0.5 inches alone that would equal 2.5 feet in real life since 1 inch is 5 feet.

Ez pz

6 0
3 years ago
Point B has coordinates ​(3​,2​). The​ x-coordinate of point A is −6. The distance between point A and point B is 15 units. What
xxTIMURxx [149]

Answer:

Distance between two points= √(x2-x1)²+(y2-y1)²

D= 15units

Let "k" be the y-coordinate of A

A(-6,k)

B(3,2)

15= √(3--6)²+(2-k)²

Taking square of both sides to eliminate the square root.

15²=(9)²+(2-k)²

225=81+4-4k+k²

k²-4k - 140=0

Using Quadratic Formula to evaluate

k= 14 or k=-10

The Possible coordinates of A are

(-6,14) or (-6,-10)

4 0
2 years ago
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Radda [10]
3 post cards and 1 newspaper can be bought
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3 years ago
If mx=x+5/x-1 and n(x) = x – 3, which function has the same domain as (m*n)(x)
Ne4ueva [31]

Answer:c

Step-by-step explanation:

Given

m\left ( x\right )=x+\frac{5}{x-1}

and n\left ( x\right )=x-3

m of n is given by replacing x in m\left ( x\right ) by x-3

m\left ( n\left ( x\right )\right )=x-3+\frac{5}{x-3-1}=x-3+\frac{5}{x-4}

m\left ( n\left ( x\right )\right ) can take any value of x except x=4 because at x=4 function is not defined

and h\left ( x\right )=\frac{11}{x-4} is also not defined for x=4 and can take any value of x

7 0
3 years ago
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