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ryzh [129]
3 years ago
9

The mosquito population is a function of rainfall, and can be approximated by the formula N(x)=−x3+45x2+1000 where x is the numb

er of inches of rainfall. Find the values of x (if any) so that the population will be a maximum? Note that x is non-negative.
Mathematics
1 answer:
KiRa [710]3 years ago
5 0

Answer:

Therefore the population will be maximum when x=30 inches.

Step-by-step explanation:

Given that, the mosquito population is a function of rainfall and can be approximated by the formula

N(x)= -x^3+45x^2+1000

where x is the number of inches of rainfall.

N(x)= -x^3+45x^2+1000

Differentiating with respect to x

N'(x)= -3x^2+90x

Again differentiating with respect to x

N''(x)=-6x+90

Now we set N'(x)=0

-3x^2+90x=0

\Rightarrow -3x(x-30)=0

\Rightarrow x=0,30

N''(0)=-6.0+90=90>0

N''(30)=-6.30+90=-90

Since at x=30, N''(x)<0, So at x=30, N(x) has maximum value.

Therefore the population will be maximum when x=30 inches.

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sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

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Therefore a_{4}=0

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The general form to the given pattern is

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Put n=10 in a_{n}=a_{n-2}-a_{n-1}

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Therefore the next 3 numbers are 3,-5,8

4 0
3 years ago
A boat can travel 333 miles on 37 gallons of gasoline. How much gasoline will it need to go 486 miles?
pochemuha
<h3>Answer:  54 gallons</h3>

Work Shown:

(distance)/(gallons used) = (distance)/(gallons used)

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333/37 = 486/x

333x = 37*486 .... cross multiplication

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x = (17,982)/333

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