so we know that the formula to get an area of a square/rectangle is A=lw, where <em>A </em>is the<em> </em><em>area</em><em>, </em><em>l</em><em> </em>is the<em> </em><em>length</em><em>, </em>and <em>w</em>is the <em>width</em><em>.</em>
we already have the area and the length, so all we need now is the width.
to find the width, simply plug in the area and the length into the formula, which will give you:
A = lw <em>-given formula</em>
12 = 5(w) <em>-plug in known variables</em>
12/5 = 5w/5 <em>-divide both sides by 5 to get x by itself</em>
2.4 = w <em>-turn the fraction into decimal if you prefer it that way</em>
First rewrite the equation in correct slope intercept form. Subtract x from both sides and then divide both sides by a negative sign.
x - y = 8
-x -x
y= x +8
A perpendicular slope is the inverse of the original slope. If the original slope is 2 then the perpendicular slope would be -1/2. In this problem the original slope is 1. The inverse of 1 is -1
So here is how we are going to get the measure of angle 2. Since given that angle COE measures 55°, we will equate <span>m∠2 = 2x and m∠3 = x+10 with 55. So, 55 = 2x + x + 10 55 = 3x + 10 55-10 = 3x 45 = 3x << divide both sides by 3 and the result is 15 = x So now that we know x, we can now solve for angle 2. </span>m∠2 = 2x m∠2 = 2(15) m∠2 = 30<span>° I hope that this is the answer that you are looking for. </span>
"For an exponential function in the form of y=ab^x, if b is between 0 and 1, what happens to the graph of the function as x increases is that <span>The graph curves down away from the x-axis.
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