No, because it is not a straight line
He would have to pay $560 because if you take 20% off of the computer using the equation 1000 - (1000 * 0.20) you get 800. This means that the 30% coupon is applied to $800, so using the same template as the equation above, we can do 800 - (800 * 0.30) to get a final answer of 560.
Answer:
c) Is not a property (hence (d) is not either)
Step-by-step explanation:
Remember that the chi square distribution with k degrees of freedom has this formula

Where N₁ , N₂m ....
are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.
Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true
The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.
Answer:
Step-by-step explanation:
From the given information:
a) To express the weekly profit as a function of price
Cost =C(q) = 1500 + 10q
Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²
Revenue = 50q - 0.1q²
Weekly profit = Revenue - Cost
P(q) = (50q -0.1q²) - (1500 + 10q)
P(q)= -0.1 q² + 40 q - 1500
However, q = 500 - 10 p using p = 50 − 0.1q
P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500
P= -10 p² + 600 p - 6500
b)
The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0
P' = 0
= -20p+600 = 0
20p = 600
p = 600/20
p = $30
c)
The maximum profit that can be made by the producer is:
P= -10(30)² + 600(30) - 6500
P = - 9000 + 18000 - 6500
P = $2500