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fiasKO [112]
3 years ago
12

Using the letters GBLAOKZE you select the A from the group without replacing the A,you select a second letter.find P(not K)

Mathematics
1 answer:
andre [41]3 years ago
5 0

Answer:

Step-by-step explanation:

After selecting A there are 6 letters that are not K out of the remaining 7 letters so

P(!K)=6/7

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The gcf of two numbers less than or equal to 12 is 2. Their LCM is 20.What are the numbers?
bixtya [17]

We know:

LCM(a,\ b)=\dfrac{ab}{GCF(a,\ b)}

We have

GCF(a,\ b)=2,\ LCM(a,\ b)=20,\ a\leq12,\ b\leq12

Substitute:

20=\dfrac{ab}{2}\qquad|\cdot2\\\\ab=40

40=1\cdot40=2\cdot20=4\cdot10=5\cdot8

Only 4 and 10 meet the requirements of the question.

--------------------------------------------------------------------

40 and 1 NOT, because 40 > 12

20 and 2 NOT, because 20 > 12

5 and 8 NOT because GCF(5, 8) = 1

5 0
3 years ago
Simplify 12n-2n⁴-10n-2n⁴+n<br><br>a. 4n⁴+3n<br>b. 3n<br>c. -4n⁴+3n<br>d. -n¹¹
Serjik [45]

The answer is C. -4n⁴+3n.


Separate the expression by its like terms.

12n-2n⁴-10n-2n⁴+n

12n+(-10n)+n=3n

-2n⁴+-2n⁴=-4n⁴


The simplified expression comes out to -4n⁴+3n.

3 0
3 years ago
Read 2 more answers
I need to solve this problem using the substitution method. I keep getting crazy numbers so I’m definitely doing something wrong
Oksanka [162]

Answer:

S=3 R=1

Step-by-step explanation:

3x1+3=6

1+(3x3)=10

3x3=9

9+1=10.

4 0
3 years ago
If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

8 0
3 years ago
X/4 -3 = 1/3 + 2x solve for x
ivann1987 [24]

Answer:

Step-by-step explanation:

\frac{x}{4} - 3 = \frac{1}{3} + 2x ...... <em>(1)</em>

(1) × 12 :

3x - 36 = 4 + 24x

21x = - 40

x = - \frac{40}{21} = -1\frac{19}{21}

4 0
3 years ago
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