see the attached figure below to better understand the problem
In this problem, we have an isosceles triangle
the measure of the other two interior angles are
2A+64 10'=180
2A=115 50'
115 50'------> convert to degrees
115+50/60=115.83 degrees
2A=115.83
A=57.92 degrees
Now we have the right triangle
tan(57.92)=x/2.100
x=2.100*tan(57.92)
<h2>x=3.35 in</h2>
Answer:
r = 16 cm
g = 34 cm
LA = 1708.16 cm^2
Step-by-step explanation:
We have that for the cone, the formula is as follows:
v = pi / 3 * r ^ 2 * h
the first thing they ask is to calculate the radius, therefore we solve for r
r ^ 2 = 3 * v / (pi * h)
replacing the volume and height, it remains:
r ^ 2 = 3 * 2560 * pi / (pi * 30)
r ^ 2 = 3 * 2560/30 = 256
r = 16
Now, to calculate the slant height, that is to say g, we can calculate it knowing the height and the radius:
g ^ 2 = r ^ 2 + h ^ 2
g ^ 2 = 16 ^ 2 + 30 ^ 2
g ^ 2 = 1156
g = 34
The lateral area of the cone is given by the following equation:
LA = pi * r * g
replacing
LA = 3.14 * 16 * 34
LA = 1708.16 cm ^ 2
the lateral area is 1708.16 cm ^ 2
N and m are numbers 3 units apart
n + 3 = m
n = m - 3
Product:
m(m-3) = 108 (ANSWER)
m^2 - 3m - 108 = 0
(m-12)(m+9)=0
m = 12(greates) and -9(void)
n = m - 3
n = 12 - 3
n = 9
therefore the two numbers are 9 and 12
Answer:
the first one is 5/12 and the second one is 6/28. Hope this helps and have a nice day:)
