Answer:
17s−109t
Step-by-step explanation:
Let's simplify step-by-step.
9(3s−3t)−2t−10(8t+s)
Distribute:
=(9)(3s)+(9)(−3t)+−2t+(−10)(8t)+(−10)(s)
=27s+−27t+−2t+−80t+−10s
Combine Like Terms:
=27s+−27t+−2t+−80t+−10s
=(27s+−10s)+(−27t+−2t+−80t)
=17s+−109t
Answer:
First term (a) =8
Common difference (d)= t2-t1
=12-8
=4
Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}
= 31/2{2×8+(31-1)4}
=31/2{16+(30×4)
=31/2(16+120)
=31/2×126
=31×63
Step-by-step explanation:
Similarly use 19 as (n) for the 19th term
X + 5y = 6
5y = -x + 6
y = -1/5x + 6/5....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So we flip -1/5 and make is -5/1....and we change the sign...making it 5/1 or just 5. So our perpendicular line will have a slope of 5.
y = mx + b
slope(m) = 5
(2,-2)...x = 2 and y = -2
sub and find b, the y int
-2 = 5(2) + b
-2 = 10 + b
-2 - 10 = b
-12 = b
so ur perpendicular equation is : y = 5x - 12 <=