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sladkih [1.3K]
3 years ago
11

Dhdjdjgdjskksnshejjejej

Mathematics
2 answers:
MakcuM [25]3 years ago
5 0

Answer: c is the answer for it

Vinvika [58]3 years ago
3 0
C is the answer.....
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WILL GIVE BRAINLIEST IF YOU ARE CORRECT!!!
Ierofanga [76]

Answer:

the first one

Step-by-step explanation:

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******WHO ANSWERS WILL BE THE BRAINLIEST********
slega [8]

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D to C

Step-by-step explanation:

The radius is half the diameter or the center point to the edge (circumference)

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Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions
quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of v_0 and F_2 be the component normal to v_0.

Since, |v_0| = 1,

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, v_0 = \left

From figure,

|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3

We know that the direction of F_1 is opposite of the direction of v_0, so we have

$F_1 = -5\sqrt3 v_0$

    $=-5\sqrt3 \left$

    $= \left$

The unit vector in the direction normal to the plane, v_1 has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5

∴  F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>

                   $=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

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3 0
2 years ago
50 points!!! Basic math!
tangare [24]

Formula for the area of the triangle:

1/2 bh

b = base

h = height

#6.

Area = 36 in²

Base = 18 in

36 = 1/2(18)h

36 = 9h

36 ÷ 9 = h

4 = h

height = 4 in

#7.

Area = 2 ft²

Height = 1 ft

2 = 1/2 b (1)

2 = 1/2 b

2 ÷ 1/2 = b

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#8.

Area = 42 in²

Base = 12 in

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Notice that the answers have no exponents (²). That is because they are used only on the area of shapes as units.

Since you find the area by multiplying things together, for example x · x = x², the exponent is there.

You do not need to worry about this being in the calculation. This will just be in units such as:

cm²

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7 0
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What is the third term of the expression<br> 4x+8y+12xy
mash [69]

Answer:

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8 0
2 years ago
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