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sladkih [1.3K]
3 years ago
11

Dhdjdjgdjskksnshejjejej

Mathematics
2 answers:
MakcuM [25]3 years ago
5 0

Answer: c is the answer for it

Vinvika [58]3 years ago
3 0
C is the answer.....
You might be interested in
The domain of y = cos x is _______.
Lana71 [14]

ANSWER

d. The set of all real numbers

EXPLANATION

The basic cosine function ,

y =  \cos(x)

is continuous everywhere.

The function is defined for all real values of x.

The domain is the set all values of x that will make the function defined.

The domain is all real numbers.

The correct choice is D.

6 0
3 years ago
What is the volume of the shape below? Use 3.14 for 8in. 3 in​
musickatia [10]
The answer is 75.4

Explanation
7 0
3 years ago
(4y − 3)(2y2 + 3y − 5)
VladimirAG [237]

Answer:

8y^3+6y^2-29y+15

Step-by-step explanation:

the correct expression is

(4y − 3)(2y^2 + 3y − 5)

Given data

We have the expression

(4y − 3)(2y^2 + 3y − 5)

let us open bracket

8y^3+12y^2-20y-6y^2-9y+15

Collect like terms

8y^3+12y^2-6y^2-20y-9y+15

8y^3+6y^2-29y+15

4 0
3 years ago
Solve the following system of equations: −2x + y = 1 −4x + y = −1
Liula [17]
Hello!

-2x + y = 1
-4x + y = -1

You can subtract these equations from each other to eliminate y

2x = 2

Divide both sides by 2

x = 1

Put this into one of the original equations

-2(1) + y = 1

Combine like terms

-2 + y = 1

Add 2 to both sides

y = 3

The answer is D) (1, 3)

Hope this helps!
6 0
3 years ago
Read 2 more answers
If j and k are nonzero integers, which pair of points must lie in the same quadrant?
Marizza181 [45]
<h3>Answer:  Choice D.   (3j, 3k)  and (3/j, 3/k)</h3>

The slash indicates a fraction.

=============================================

Proof:

We'll need to consider 4 different cases.

-----------------------

Case (1): j > 0 and k > 0

If j > 0, then 3j > 0 and 3/j > 0

If k > 0, then 3k > 0 and 3/k > 0

The two points (3j, 3k) and (3/j, 3/k) are both in quadrant 1.

-----------------------

Case (2): j > 0 and k < 0

If j > 0, then 3j > 0 and 3/j > 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are both in quadrant 4.

------------------------

Case (3): j < 0 and k > 0

If j < 0, then 3j < 0 and 3/j < 0

If k > 0, then 3k > 0 and 3/k > 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 3.

------------------------

Case (4): j < 0 and k < 0

If j < 0, then 3j < 0 and 3/j < 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 4.

------------------------

For nonzero integers j and k, we've shown that Points (3j, 3k) and (3/j, 3/k) are in the same quadrant. This concludes the proof.

8 0
3 years ago
Read 2 more answers
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