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3 years ago

Which equation in slope-intercept form represents a line that is parallel to y=−4x−5 and passes through the point (0,0)?

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

Answer:

$\displaystyle y = -4x$

Step-by-step explanation:

0 = 0 ± b

$\displaystyle 0 = b \\ \\ y = -4x$

* Parallel Lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>], so −4 remains the way it is.

I am joyous to assist you anytime.

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DochEvi [55]

Answer:

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3 years ago

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Sixty percent of the customers who go to Sears Auto Center for tires buy four tires and 22% buy two tires. Moreover, 14% buy few

Bezzdna [24]

Answer:

There is a 4% probability that a customer buys three tires.

Step-by-step explanation:

We have those following percentages

60% buy four tires. This is also the probability that someone buys four tires.

22% buy two tires

14% buy fewer than two tires(one or none).

P% buy three tires

The sum of the percentages must be 100%.

$60 + 22 + 14 + P = 100$

$96 + P = 100$

$P = 4$

There is a 4% probability that a customer buys three tires.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=4%20%20%20%7B%7D%5E%7Bx%20%7D%20%20%2B%206%20%7B%7D%5E%7Bx%7D%20%3D%209%20%7B%7D%5E%7Bx%7D%20%

Nookie1986 [14]

So, the value of x is 1.19

The question is an exponential equation

<h3>What is an exponential equation?</h3>

An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.

Since $4^{x} + 6^{x} = 9^{x}$ ,

Dividing through by 4ˣ, we have

$\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} } = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} } = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3}{2})^{2x} }$

Let y = (3/2)ˣ

So,

1 + y = y²

y² - y - 1 = 0

Using the quadratic formula to find y,

$y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

where a = 1 b = -1 and c = -1

Substituting the values of the variables into the equation, we have

$y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or \frac{3.236}{2}\\= -0.618 or 1.618$