Question

When the sun has risen 32 degrees above the horizon, Sandy casts a shadow that is 9 feet 2 inches long. How tall is Sandy, to the nearest inch?

Answer 1

Answer:

The height of Sandy is 68.74 inches.

Step-by-step explanation:

It is given that the sun has risen 32 degrees above the horizon. It means the angle of elevation is 32°.

Let the height of Sandy be x.

Sandy casts a shadow that is 9 feet 2 inches long.

We know that 1 feet = 12 inches

Using this conversion, we get

Shadow = 9 feet 2 inches = 9(12)+2 = 110 inches

In a right angled triangle,

$\tan\theta =\frac{perpendicular}{base}$

In triangle ABC,

$\tan(\angle C)=\frac{AB}{BC}$

$\tan(32^{\circ})=\frac{x}{110}$

Multiply both sides by 110.

$110\tan(32^{\circ})=x$

$68.73562871=x$

$x\approx 68.74$

Therefore the height of Sandy is 68.74 inches.