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arsen [322]
4 years ago
6

What is 7/10-1/2 for subtracting fractions

Mathematics
2 answers:
riadik2000 [5.3K]4 years ago
8 0
\frac{7}{10} -  \frac{1}{2} \\ 
 \\  \frac{7x1}{10x1}= \frac{7}{10} \\ 
 \\  \frac{1x5}{2x5}= \frac{5}{10} \\ 
 \\  \frac{7}{10} -  \frac{5}{10}= \frac{2}{10} \\ 
 \\ Solution: \frac{2}{10}
Charra [1.4K]4 years ago
7 0
I'm guessing you mean to find the answer. So find a common denominator, which is 10. You can leave 7/10 alone. Now multiply by 5 on both the numerator and denominator of 1/2. It would be 5/10. Now subtract 7/10-5/10. The answer is 2/10. It can be simplified to 1/5. The answer now would be: 1/5
I hope this helps. :-) 
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Answer:

a^2.

Step-by-step explanation:

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Can anybody help me out?
charle [14.2K]

You need to isolate the "x" in both inequalities

5x + 7 ≤ -3     Subtract 7 on both sides

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x ≤ -2


3x - 4 ≥ 11     Add 4 on both sides

3x ≥ 15  Divide 3 on both sides

x ≥ 5


This is your simplified inequalities:

5x + 7 ≤ -3 or 3x - 4 ≥ 11   --------->     x ≤ -2 or x ≥ 5      Your answer is A

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A. Use the composition to prove whether or not the functions are inverses of each other.
shtirl [24]

Here we need to find fog and gof, and they must be equal to x .

Let's check out fog

fog = f(g(x))

f(\frac{4x+1}{x})

Substituting the value of g(x) in f(x) for x, we will get

\frac{1}{\frac{4x+1}{x}-4}  =\frac{1}{\frac{4x+1-4x}{x}}=x

Domain

Here the input function is g(x), and the denominator should not be 0. So x should not be zero. Therefore, domain is

(-\infty,0)U(0, \infty)

Now let's check gof

gof = g(f(x))

Here we need to insert f(x) in g(x) for x, and on doing that , we will get

\frac{4(\frac{1}{x-4})+1}{\frac{1}{x-4}}   = \frac{4+x-4}{1}=x

Domain

Here the input function is f(x), and denominator should not be zero.

SO domain is

(- \infty,4)U(4, \infty)

Since fog = gof =x, so the given function are inverses of each other .

8 0
3 years ago
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