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arsen [322]
3 years ago
6

What is 7/10-1/2 for subtracting fractions

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
8 0
\frac{7}{10} -  \frac{1}{2} \\ 
 \\  \frac{7x1}{10x1}= \frac{7}{10} \\ 
 \\  \frac{1x5}{2x5}= \frac{5}{10} \\ 
 \\  \frac{7}{10} -  \frac{5}{10}= \frac{2}{10} \\ 
 \\ Solution: \frac{2}{10}
Charra [1.4K]3 years ago
7 0
I'm guessing you mean to find the answer. So find a common denominator, which is 10. You can leave 7/10 alone. Now multiply by 5 on both the numerator and denominator of 1/2. It would be 5/10. Now subtract 7/10-5/10. The answer is 2/10. It can be simplified to 1/5. The answer now would be: 1/5
I hope this helps. :-) 
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If cos 0=2/3, what are the values of sin 0 and tan 0?
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Answer:

Below

Step-by-step explanation:

● cos O = 2/3

We khow that:

● cos^2(O) + sin^2(O) =1

So : sin^2 (O)= 1-cos^2(O)

● sin^2(O) = 1 -(2/3)^2 = 1-4/9 = 9/9-4/9 = 5/9

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So we deduce that tan O will have two values since we don't khow the size of O.

■■■■■■■■■■■■■■■■■■■■■■■■■

●Tan (O) = sin(O)/cos(O)

● tan (O) = (√(5)/3)÷(2/3) or tan(O) = (-√(5)/3)÷(2/3)

● tan (O) = √(5)/2 or tan(O) = -√(5)/2

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Marla made an error when solving the equation shown. What was her error, and how should she fixt it?​
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Divide x^3 -3x^2 by x-2<br> . Step 1 - Fill in the missing number:
vagabundo [1.1K]

Answer:


Step-by-step explanation:

First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items

F(x) = x^3-3x^2+0x+0

We have to divide this by x-2

Leading terms in the dividend and divisor are

x^3  and x

Hence quotient I term would be x^3/x=x^2

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

Multiply x-2 by x square and write below the term and subtract

We get  

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

                                                         ---------------

-x^2+0x

Again take the leading terms and find quotient is –x

                                                x-2) x^3-3x^2+0x+0(x^2-x

x^3-2x^2

                                                         ---------------

-x^2+0x

                                                                  -x^2-2x

Subtract to get 2x +0 as remainder.

                                                  x-2) x^3-3x^2+0x+0(x^2-x-2

x^3-2x^2

                                                         ---------------

-x^2+0x

                                                                  -x^2+2x

                                                          -------------

                                                                      -2x-0

                                                                              -2x+4

                                                             ------------------

                                                                               -4

Thus remainder is -4 and quotient is x^2-x-2


8 0
3 years ago
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