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3 years ago

If f(x) = 22 + 1, what is f(x) when x = 3? O 1 O 7 13 O 19

Mathematics

1 answer:

Luda [366]3 years ago

4 0

Answer:

Step-by-step explanation: Sit on the couch and think about the answer while eating cheese puffs and watching reruns of Looney Tunes and then jot down the formula of:

IF f(x)= 22+1 THEN f(x) when x=3 is 7

The answers come so quickly when I ask my magic 8 Ball and I said is 7 the answer? It replied Most Likely so it would be B the correct answer!

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One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago

Multiply the sum of 7/8 and 3/4 by the differences of 5/36 from 11/13

Anni [7]

Answer:

$=-\frac{331}{288}=-1.14930\dots$

Step-by-step explanation:

$(\frac{7}{8} + \frac{3}{4} )\times (\frac{5}{36} - \frac{11}{13} )\\\\\mathrm{Join}\:\frac{7}{8}+\frac{3}{4}:\quad \frac{13}{8}\\\\=\frac{13}{8}\left(\frac{5}{36}-\frac{11}{13}\right)\\\\\mathrm{Join}\:\frac{5}{36}-\frac{11}{13}:\quad -\frac{331}{468}\\\\=\frac{13}{8}\left(-\frac{331}{468}\right)\\\\=-\frac{13}{8}\times\frac{331}{468}\\\\\mathrm{Cross-cancel\:common\:factor:}\:13\\=\frac{1}{8}\times\frac{331}{36}\\\\=-\frac{1\cdot \:331}{8\times\:36}\\\\=-\frac{331}{288}$

4 0

3 years ago