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DENIUS [597]
3 years ago
10

(x2 - x - 2) ÷ (x - 2)

Mathematics
2 answers:
Semmy [17]3 years ago
8 0

Answer:

x + 1

Step-by-step explanation:

(x² − x − 2) / (x − 2)

Factor the numerator.  Using the AC method:

ac = (1)(-2) = -2

Factors of -2 that add up to -1 are -2 and 1

Divide by a and reduce: -2/1 and 1/1

The factors are (x − 2) and (x + 1)

(x − 2) (x + 1) / (x − 2)

Divide:

x + 1

kifflom [539]3 years ago
7 0

Answer:

(x+1)

Step-by-step explanation:

(x^2-x-2)/(x-2)=(x+1)

Because (x-2)(x+1)=x^2-2x+x-2=x^2-x-2.

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Graph the line whose y intercept is 9 and whose x intercept is 4
11Alexandr11 [23.1K]
The equation for this line would be y=((-4/9)x)+4

8 0
2 years ago
After college graduation, Mario received employment offers from two companies. The first company offered a yearly salary of $31,
Alexandra [31]
The first thing we must do for this case is to define a variable:
 x: number of years
 y: total salary
 We have then:
 For first company:
 y = 1500x + 31000
 For second company:
 y = 2000x + 28500
 Equaling both equations we have:
 1500x + 31000 = 2000x + 28500
 Clearing x:
 2000x - 1500x = 31000 - 28500
 500x = 2500
 x = 2500/500
 x = 5
 Answer:
 
It will take for the salaries to be the same about:
 
x = 5 years
3 0
2 years ago
A bag contains 8 yellow marbles and 6 blue. What number of yellow marbles can you add to the bag so that the ratio of yellow to
Kazeer [188]
8 : 6 ...add 7 yellow and it becomes 15:6 when reduced = 5:2
6 0
2 years ago
Read 2 more answers
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
In ∆ABC, point D is the centroid. If (AE) ̅=15, (BF) ̅=27, and (CD) ̅=8, find the following lengths
Anna71 [15]

Answer:

5,18,12 cms are the answer.

Step-by-step explanation:

Given is a triangle ABC.  Point D is the centroid.  

E,F and G are midpoints of CB, BA and AC respectively.

AE, BF and CG are medians of the triangle.

We know that centroid divides the median in the ratio 2:1

Using this we find that AD:DE = 2:1

Or AD+DE:DE = (2+1):1

AE:DE =3:1

15:DE = 3:1 . Hence DE =5 cm.

On the similar grounds we find that DF = 1/3 BF = 9

Hence BD = DF-BF = 27-9 =18 cm

and also

CG = 3/2 times CD = 12 cm.

7 0
2 years ago
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