Answer:
2 complex roots
Step-by-step explanation:
The function f(x)=x^5+4x^3−5x can be factored as follows:
f(x)=x(x^4+4x^2−5). One root, a real root, is zero.
That leaves g(x) = x^4+4x^2−5. Substitute p = x^2, obtaining p^2 + 4p - 5 = 0. This factors as follows: (p+5)(p-1) = 0. Thus, p = -5 and p = 1.
Recalling that p = x^2, we have -5 = x^2 and +1 = x^2. The latter yields x = 1 and x = -1. The former yields +i√5 and =i√5.
Thus, the given poly has 3 real zeros: -1, 1 and 0. Due to the imaginary roots shown above, this means that this poly has 2 complex roots.
Answer:
Option (4) is correct about BQ
Step-by-step explanation:
Given : From the figure : ∠BQA = 54° and ∠BAQ = 36°
Now, Since ∠BAQ = 36° > 30°
So, ∠BAQ is not acute.
⇒ (1) is rejected.
Also, ∠BQA = 54° > 30°
So, ∠BQA is not acute.
⇒ (2) is rejected.
Now, in ΔABQ, By using angle sum property of a triangle
∠BAQ + ∠BQA + ∠ABQ = 180°
⇒ 36° + 54° + ∠ABQ = 180°
⇒ ∠ABQ = 90°
Since, ∠ABQ is right angle so, (3) is rejected.
Now, ∠ABQ = 90° and the line which is exterior to the circle and makes right angle with the radius of the circle is always tangent to the circle.
Hence, Option (4) is correct about BQ.
Therefore, BQ is a tangent line because m∠ABQ = 90°
Answer:
i belive it is answer B
Step-by-step explanation: