The scale factor is some number between 0 and 1 (not including either endpoint) because the image is smaller than the preimage.
Triangle ABC is the preimage, or the "before"; while triangle A'B'C' is the image, which is the "after".
preimage ----> image
before ----> after
Step-by-step explanation:
If I'm not wrong it should be 27.93
Answer:
No... provided no other information or no graph is provided.
Step-by-step explanation:
You can find the x-coordinate of the vertex which can be calculated using the two given x-intercepts. Using the symmetry of the parabola, it would just mean the vertex should lay midway between the x's. So the x-coordinate of the vertex is (12+35)/2=47/2.
However, we do not have enough information about the relationship between x and y to find the y-coordinate of the vertex.
All we are given is y=a(x-12)(x-35) (where a is real number) since we know the relationship is quadratic, and the zeros are 12 & 35.
So we could have many possible y-coordinates for our vertex since we don't know the value of a in our equation and we can plug in our x-coordinate for our vertex to find them all.
y=a(47/2-12)(47/2-35)
I'm just going to put everything to right of a in calculator:
y=-529/4 ×a
So that's all the possible y-coordinates for the vertex.
Answer: -5t + 23= 18
Step-by-step explanation: 18 + -3 + -5t + 8 =
(-5t ) + (18 + -3 + 8) = -5t + 23 → 18
Answer:
A is a function; B, C and D are not.
Step-by-step explanation:
In other words: Identify the sole function among these relationships.
A function maps any input onto exactly one output.
If a relationship maps any input onto more than one output, it is not a function.
Thus, we eliminate B, C and D. In B, for example, we have the inputs {1, 2, 3}, where the '1' has two y-values associated with it.
On the other hand, A has the domain {-1, 0, 1, 2}, and all four inputs have exactly one associated output.
