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sammy [17]
3 years ago
11

Julie needs to cut 4 pieces of yarn, each with the same length, and a piece of yarn 7.75 inches long. Let y represent the length

of each of the equal pieces of yarn that Julie decides to cut. What is the equation that can be used to determine the total length of all of the yarn that she ends up cutting, t? Is the graph of the equation continuous or discrete?
Mathematics
2 answers:
Vlad [161]3 years ago
6 0

t=4y+7.75; continuous.

I hope this helps!

Y_Kistochka [10]3 years ago
3 0

Answer:

\text{t}=4\text{y}+7.75, the graph will be continuous.

Step-by-step explanation:

Given: Julie needs to cut 4 pieces of yarn, each with the same length, and a piece of yarn 7.75 inches long, y represent the length of each of the equal pieces of yarn that Julie decides to cut, t represents total length of yarn.

To Find: Equation to determine the total length of yarn, and find if graph is discrete or continuous.

Solution:

total number of piece to be cut from yarn = 5

length of four equal pieces of yarn=\text{y}

length of fifth piece of yarn  =    7.75\text{inches}

now,

total length of yarn \text{t} is

              \text{t}=7.75+4\text{y}

rewriting equation

              \text{t}=4\text{y}+7.75

as length of piece of yarn \text{y} can be any real number, the graph will be continuous.

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3 years ago
How would the factor pairs change if nancy had only 5 posters to arrange?
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Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

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5x2 -----> 5 rows of 2 posters

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therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

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therefore

Nancy can arrange the posters in 2 ways

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