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Nostrana [21]
2 years ago
8

One number is 4 times as large another. The sum of their reciprocals is 45/4. Find the two numbers

Mathematics
2 answers:
AfilCa [17]2 years ago
8 0
<em>9 because 9*5=45 that the answer I hope you like it </em><em />
Reptile [31]2 years ago
7 0
Let, 
the numbers be "x" and "y"
According to the question,
x = 4y ......................................................equation (1)

\frac{1}{x} + \frac{1}{y}= \frac{45}{4}...................................equation (2)

Taking equation (2)
\frac{1}{x} + \frac{1}{y}= \frac{45}{4}

Substituting the value of "x" from equation (1), we get,

\frac{1}{(4y)} + \frac{1}{y}= \frac{45}{4}

\frac{1}{4y} + \frac{1}{y}* \frac{4}{4} = \frac{45}{4}

\frac{1}{4y} + \frac{4}{4y}= \frac{45}{4}

\frac{1+4}{4y} = \frac{45}{4}

\frac{5}{4y} = \frac{45}{4}

Cross multiplying, we get,

5*4 = 45*4y

20 = 180y
<u />
\frac{20}{180}  = y

\frac{1}{9}  = y

y =  \frac{1}{9}

Now,
Taking equation (1)
x = 4y
Substituting the value of "y", we get

x = 4( \frac{1}{9} )

x= \frac{4}{9}

So, the numbers are \frac{1}{9} and \frac{4}{9}

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