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Inga [223]
3 years ago
15

Mallory puts $1.00 in a jar. The following week, she puts 2 times that original amount in the jar. For each of the next six week

s, Mallory continues to double the amout of money she places in her savings jar each week.
Determine if the relationship is linear or nonlinear. Explain your choice using examples with ordered pairs. (week, amount)
Mathematics
2 answers:
Burka [1]3 years ago
8 0

The relationship of the ordered pair that represents Mallory savings is a nonlinear relationship.

Let x represents the number of weeks, and y represents the amount put in the jar, each week.

So, we have the following highlights for 6 weeks.

  • Week 1: (1, 1)
  • Week 2: (2,2)
  • Week 3: (3,4)
  • Week 4: (4,8)
  • Week 5: (5,16)
  • Week 6: (6,32)

The ordered pairs can then be represented as:

(x,y) = (1,1)(2,2)(3,4)(4,8)(5,16)(6,32)

As the x values increase, the y values increase too, but the y values do not increase at a constant rate.

This means that the relationship is not linear; it is an exponential relationship.

Hence, the relationship is a nonlinear relationship.

Read more about linear relationships at:

brainly.com/question/7040405

madam [21]3 years ago
5 0

We want to see if the relationship between the number of weeks and the money put in the jar is linear or not, we will see that this is not a linear equation (it is exponential).

So a linear relation is something like:

y = a*x + b

Note that for any value of x, an increase of 1 unit gives:

y = a*(x+ 1) + b = (a*x + b) + a

So for increases of 1 unit in the x-value, we have increases of "a" units on the y-value.

In the given situation we have:

  • In week 1 she puts $1.00 in the jar.
  • In week 2 she puts $2.00 in the jar (now the jar has $3.00 in it)
  • In week 3 she puts $4.00 in the jar (now the jar has $7.00 on it)
  • In week 4 she puts $8.00 in the jar (now the jar has $15.00 on it)

and so on.

Writing that as points we have:

(1, $1)

(2, $3)

(3, $7)

(4, $15)

Notice that for equal increases in the x-value, (increases of 1 unit) we don't equal increases in the y-value (first increases by $2, then by $4, etc...) So this is not a linear equation, this is actually exponential.

If you want to learn more, you can read:

brainly.com/question/19770987

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Shalnov [3]

The answer to these two questions are not the same. We don't agree with Noah.

Reason:

Let's start with the first question.

1. Given: rate = 10% increase, base/original number = 550 bison

10% of 550 is:

.10\times550bison=55bison

10% of 550 is 55. Hence, there is an increase of 55 bison this year. This year, there are 550 + 55 = 605 bison in the herd.

2. Given: rate = 10% decrease, percentage/final number = 550 bison

Applying the concept of Percentage = Base x Rate, we can get the Base or the original number of bison before the decrease by dividing Percentage over Rate.

\text{Base}=\frac{\text{Percentage}}{\text{Rate}}

Filling in the formula with the given values in question 2, we have:

\text{Base}=\frac{550}{1-.10}=\frac{550}{.90}=611.11\approx611bison

Last year, there were 611 bison.

As we can see, the answer for number 1 is 605 bison while the answer for the number 2 is 611 bison. The answer of the two questions are not the same.

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How will the graph of g(x) = 8x-1 differ from the graph of f(x) = 8x ?
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Lydia is an architect. She has to design a courtyard garden inside a new hotel. On her blueprint, which is 1/20 the size of the
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Answer:

720 inches

Step-by-step explanation:

On her blueprint, which is 1/20 the size of the actual garden

the width of the garden is 36 inches.

What is the width of the actual garden?

Let width of the actual garden = x

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x = 720 inches

The width of the actual garden = 720 inches

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