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lubasha [3.4K]
3 years ago
13

On which number line do the points represent negative 4 and 1 over 2 and +3? (4 points)

Mathematics
2 answers:
Keith_Richards [23]3 years ago
8 0

Answer:

idk

Step-by-step explanation:

Sphinxa [80]3 years ago
7 0

Answer:

first of all calm down babe everything is going to be okay i will give you my answer for you could get it okay

Step-by-step explanation:

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The temperature readings from a thermocouple in a furnace fluctuate according to a cumulative distribution function,
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Answer:

P(x

P(x

P(x>808.40) = 0.58

P(x\le805.40\ or\ x\ge 808.40) = 0.85

Step-by-step explanation:

Given:

F(x) = \left\{\begin{array}{ll}{0} &; {x

Solving (a): P(x < 810)

To solve this, we make use of:

P(x

Because

800^\circ C \le 810 \le 820^\circ C

So:

F(x) = 0.05 * 810 -40

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P(x

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P(x

Because:

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P(x

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Here, we make use of complement rule:

P(x>808.40) = 1 - P(x \le 808.40)

Where:

P(x\le808.40) = 0.05x - 40

P(x\le808.40) = 0.05*808.40 - 40

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So:

P(x>808.40) = 1 - 0.42

P(x>808.40) = 0.58

Solving (d) The probability that the temperature lies outside 805.60 and 808.40

First, we calculate the probability that it lies within.

This is represented as:

P(805.40 < x < 808.40)

This is calculated using:

P(805.40 < x < 808.40) = F(808.40) - F(805.40)

P(805.40 < x < 808.40) = 0.05*808.40-40 - (0.05*805.40-40)

P(805.40 < x < 808.40) = 0.42 - (0.27)

P(805.40 < x < 808.40) = 0.42 - 0.27

P(805.40 < x < 808.40) = 0.15

Using complement rule, the required probability is:

P(x\le805.40\ or\ x\ge 808.40) = 1 - 0.15

P(x\le805.40\ or\ x\ge 808.40) = 0.85

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