If angle 7 has a measure of 153° in the given diagram, what is the measure of angle 6

#5 Antonio and Abby had the same nimber of paperclips. After Antonio gave 30 paperclips to Abby, Abby had twice as many papercli

Kay [80]

Answer:

#5: 180 paperclips in total.

#6: 126 stamps in total.

#7: Elena should give Lucy 15 colored pencils.

Step-by-step explanation:

This explanation solves each question by setting a single unknown, $x$ .

Let $x$ the initial number of paperclips of Antonio. That should also be the number of Abby's paperclips.

Initially:

Antonio: $x$ paperclips;
Abby: $x$ paperclips.

Antonio gives $30$ paperclips to Abby. After that,

Antonio: $(x - 30)$ paperclips;
Abby: $x + 30$ paperclips.

Abby now possess twice as many paperclips as Antonio does. In other words,

$2(x - 30) = x + 30$ .

By the distributive property:

$2x - 60 = x + 30$ .

Substract $x - 60$ from both sides

$x = 30 - (-60) = 90$ .

Both Antonio and Abby initially possess 90 paperclips. That's 180 in total.

Similarly, let $x$ be the number of Emily's stamps. That should be the same as the number of Jasmine's stamps.

Initially:

Emily: $x$ stamps;
Jasmine: $x$ stamps.

After Emily gives $42$ stamps to Jasmine:

Emily: $x-42$ stamps;
Jasmine: $x+42$ stamps.

Jasmine now possesses twice as many stamps as Emily does. In other words,

$2(x-42) = x+42$ .

$x = 42 + 2\times 42 = 126$ .

Jasmine used to possess 126 stamps. Now she possesses $126 + 42 = 168$ stamps after receiving $42$ stamps from Emily.

Let the number of pencils that Elena needs to give to Lucy be $x$ .

Initially:

Elena: 60 pencils;
Lucy: 26 pencils.

After Elena gives $x$ pencils to Lucy:

Elena: $60 - x$ pencils;
Lucy: $26 + x$ pencils.

Elena should now possess four more pencils than Lucy does. In other words,

$\underbrace{60 - x}_{\text{Elena's}} = \underbrace{(26 + x)}_{\text{Lucy's}} +4$ .

$2x = 30$ .

$x = 15$ .

8 0

3 years ago

Estimate 19.164 - 9.53 by first rounding each number to the nearest tenth.

Lina20 [59]

19.164 can be rounded to 19.2. That is because 0.164 is closer to 0.2 than it is to 0.1

9.53 rounded the the nearest tenth is 9.5 because 0.53 is closer to 0.5 than it is to 0.6.

19.2 - 9.5 = 9.7

Your answer is 9.7

3 0

3 years ago

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If a jar of salad dressing costs $3.99 for 12 Ounces. How much does it cost per tablespoon?

romanna [79]

I ounce is 2 tablespoons so do 12 times 2 and that is 24 then multiply 3.99 times 2 thats your answer 7.98

4 0

3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

What is the area of the figure graphed below?

Vedmedyk [2.9K]

A i think sorry if i’m wrong

5 0

3 years ago

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