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Oxana [17]
3 years ago
14

Which are the solutions of x2 = –5x + 8?

Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

As exact answers:

x=\frac{-5-\sqrt{57} }{2}  and  x=\frac{-5+\sqrt{57} }{2}

As decimal answers:

x = -6.2749172 ≈-6.3

x = 1.27491722 ≈  1.3

Step-by-step explanation:

For quadratic equations, you can use the quadratic formula. Rearrange the equation to standard from, which is ax² + bx + c = 0.

x² = –5x + 8

x² + 5x - 8 = 0

State the values for "a", "b" and "c",

a = 1; b = 5; c = -8

x=\frac{-b±\sqrt{b^{2}-4ac} }{2a}            (Ignore the Â, it's a formatting error)

x=\frac{-5±\sqrt{5^{2}-4(1)(-8)} }{2(1)}           Simplify

x=\frac{-5±\sqrt{25-(-32)} }{2}               Two negatives make a positive

x=\frac{-5±\sqrt{57} }{2}  

Split the equation at the ± for plus and minus:

x=\frac{-5+\sqrt{57} }{2}  = 1.27491722 ≈ 1.3

x=\frac{-5-\sqrt{57} }{2}  = -6.2749172 ≈ -6.3

Therefore the solutions are 1.3 and -6.3.

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Which of the following is equivalent to 25x2+16−40x−64y2? Select two.
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The equivalent expression to the given expression 25x²+16−40x−64y² are; (5x-4)²−64y² and (5x−4−8y)(5x+4+8y)

<h3>Difference of two squares</h3>

According to the question:

  • We are required to determine the equivalent expression.

When we try to factorise the given expression systematically; we have;

  • 25x²+16−40x−64y² = (25x²+16−40x)−64y²

By the difference of two squares concept;

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