Answer:
Statements Reasons
1.
1. Given
2.
2. Given
3.
3. Base angles theorem.
4.
4. Alternate interior angles.
5.
5. Alternate interior angles.
6.
6. Isosceles triangle theorem.
7.
7. Vertical angles.
8.
8. By SAS postulate.
9.
9. By CPCTC.
10. 10. Sum of adjacent angles.
![m\angle MAK + m \angle NAC = m \angle NCK + m \angle MCA\\m \angle A = m \angle C](https://tex.z-dn.net/?f=m%5Cangle%20MAK%20%2B%20m%20%5Cangle%20NAC%20%3D%20m%20%5Cangle%20NCK%20%2B%20m%20%5Cangle%20MCA%5C%5Cm%20%5Cangle%20A%20%3D%20m%20%5Cangle%20C)
11.
is isosceles 11. Base angles theorem.
Answer:
Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.
Step-by-step explanation:
Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.
Answer:
it's •3
Step-by-step explanation:
1/100 × 300/1 =3
100 into 300 is 3
then equal to 3/1
any number over one is it self
Answer:
A
Step-by-step explanation:
The formula for this type of interest is
, where A is the total amount, P is the initial investment, x is the interest rate, n is the amount of times that the investment is compounded a year, and t is the amount of years. Plugging in the numbers given, you get:
![A=1800(1+\frac{0.025}{2})^{2\cdot 12}=](https://tex.z-dn.net/?f=A%3D1800%281%2B%5Cfrac%7B0.025%7D%7B2%7D%29%5E%7B2%5Ccdot%2012%7D%3D)
![1800(1.0125)^{24}\approx 2425.23](https://tex.z-dn.net/?f=1800%281.0125%29%5E%7B24%7D%5Capprox%202425.23)
Now, she invests this into a new account, and you can set up the following equation:
![A=2425.23(1+\frac{0.04}{12})^{12\cdot 7}=](https://tex.z-dn.net/?f=A%3D2425.23%281%2B%5Cfrac%7B0.04%7D%7B12%7D%29%5E%7B12%5Ccdot%207%7D%3D)
, or option A.
Hope this helps!
Answer:
- y = x - 6
- y = -x + 5
- y = x - 5
Step-by-step explanation:
<em>Slope - intercept formula: y = mx + b, where m- slope, b- y-intercept</em>
<u>1. Points are:</u>
<u>Slope is:</u>
- m = (y2 - y1)/(x2 - x1)
- m = (-2 - (-4))/(4 - 2) = 2/2 = 1
y-intercept is - 6 as per graph
<u>Then the formula is</u>
<u>2. Points are:</u>
<u>Slope is:</u>
- m = (1 - 5)/(4 - 0) = -4/4 = -1
y-intercept is 5 as per point
<u>Then the formula is</u>
<u>3. Points are:</u>
<u>Slope is</u>
- m = (3 - 1)/(-1 -(-3)) = 2/2 = 1
y-intercept is -5 as per graph
<u>Then the formula is</u>