Answer:
The angle is 1560°
Step-by-step explanation:
The length of an arc in radian is given by s=rФ
where s=length of an arc, r=radius and Ф = angle in radians
The question asked us to find the angle
Given to us is; r =6m and s=52π and Фis what we are to find
From the formula s= rФ
Ф= s/r = 52πm/6m
Ф=52π/6
Ф=26π/3 radians
But the question states that the angle should be in degree, so we will change the above angle to degree, to do that we will simply multiply the angle by 180°/π
Thus;
Ф=26π/ 3 × 180°/π
(The π at the numerator will cancel that of the denominator, and 180° will be divided by 3 to give 60°, we will be left with just 26 and 60 at the numerator)
Ф = 26× 60°
Ф=1560°
Therefore, the central angle (in degree) subtended by an arc with length 52πmeters and radius 6 meters is 1560°
Answer:b
Step-by-step explanation:
The terms in Pattern B are one third the corresponding terms in Pattern A.
Answer:
A. cd4
Step-by-step explanation:
You just multiply the top and bottom numbers like it was two normal multiplication problems. Ex. 3/4x1/4=3/16 (3x1,4x4) But its different because you have to put them together to make a fraction (3/16).
Answer:
Step-by-step explanation:
Hello!
I'll express all the given percentages as probabilities:
Given the events:
Banking online (Bo)
Under the age of 50 (<50)
P(Bo)= 0.30
P(<50)= 0.40
P(Bo ∩ <50)= 0.25
1) What percentage of adults do not conduct their banking online?
The event "adults that do not conduct their baking online" is the complement of the event "adults that conduct their baking online" Symbolically 
P()= 1 - P(Bo)= 1 - 0.30 = 0.70
2) What type of probability is 25%?
The probability P(Bo ∩ <50)= 0.25 is a joint probability, it indicates the intersection between both events.
3) Construct a contingency table showing all joint and marginal probabilities.
Check attachment.
4) What is the probability that an individual conducts banking online given that the individual is under the age of 50?
Symbolically:
P(Bo/<50)= <u> P(Bo ∩ <50) </u> = <u> 0.25 </u> = 0.625
P(<50) 0.40
I hope it helps!
