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Fofino [41]
3 years ago
5

M What is Enter your answer in the box.

Mathematics
1 answer:
noname [10]3 years ago
5 0

Answer:

you

Step-by-step explanation:

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Which graph represents the function f (x) = 5 - 5x^2
svetlana [45]
The bottom one is correct
6 0
4 years ago
Calculate the average speed of a complete round trip in which the outgoing 300 km is covered at 97 km/h, followed by a 1.0-h lun
gizmo_the_mogwai [7]

Answer:

Average Speed  is 65 km/hr

Step-by-step explanation:

To get the average speed,  first we have to calculate the time spent in the round trip .

Speed= Distance/ time

So,  Time= Distance/Speed

Time Outgoing= 300km/ 97km/hr

Time Outgoing=3.0927 hr

Time lunch break =1 hr

Time return= 300km/ 58km/hr

Time Outgoing=5.1724 hr

Total= 3.0927 hr+1 hr+5.1724 hr=9.2651

To get average speed,  we have to divide all the distance by the time it took al the trip.

Average Speed= Distance/ time

Average Speed= 600km/9.2651 hr= 64,76 km/hr

Average Speed=64,76 km/hr ≅ 65km/hr

3 0
3 years ago
Plssss helpppp ASAPP<br> will mark BRAINLIEST!!!
Snezhnost [94]

Answer:

I would say the last one

Step-by-step explanation:

The third works the same way but 46/17 is hard to calculate without a calculator

5 0
4 years ago
Read 2 more answers
Julie earned $25 this is 5 times as much as what Lisa earned how much did Lisa earn
NISA [10]
If $25 is 5 times what Lisa earned, we simply divide that $25 by 5 to find that her earnings were $25 ÷ 5 = $5.
4 0
3 years ago
Read 2 more answers
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?
olga2289 [7]

Step 1

<u>Find the slope of the given line</u>

Let

A(-3,2)\ B(2,-1)

slope mAB is equal to

mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}

Step 2

<u>Find the slope of the line that is perpendicular to the given line</u>

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}

Step 3

<u>Find the equation of the line with mCD and the point (3,0)</u>

we know that

the equation of the line in the form point-slope is equal to

y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5

Multiply by 3 both sides

3y=5x-15

5x-3y=15

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation 5x-3y=15

4 0
3 years ago
Read 2 more answers
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