The machine was operated for 4.5 hours
A machine uses gasoline at a rate of 1/5 gallon per hour
The number of hours it will take the machine to use 9/10 gallon can be calculated as follows
1/5 = 1
9/10= x
cross multiply
1/5x= 9/10
0.2x= 0.9
x= 0.9/0.2
x= 4.5
Hence the machine was operated for 4.5 hours
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Answer:
8.04672
Step-by-step explanation:
Answer:
x = 2.67°
GKJ = 40°
Step-by-step explanation:
Angle HKJ = 6x + 4
Angle HKG = 9x - 4
Segment bisects Angle GKJ, it means that angle HKJ is the same as angle HKG.
You have the measure of both angles in terms of x.
Angle HKJ = Angle HKG
6x + 4 = 9x - 4
4 + 4 = 9x - 6x
8 = 3x
2.67 = x
Angle HKJ:
6(2.67) + 4 = 20°
Angle HKG:
9(2.67) - 4 = 20°
Angle GKJ = HKJ + HKG = 20 + 20 = 40°
Answer:
54
Step-by-step explanation:
What the shorthand is telling you is wherever you see an x on the right, you put in -8
f(x) = 6(1- x)
f(-8) = 6(1 - - 8)
f(-8) = 6(1+8)
f(-8) = 6*9
f(-8) = 54
3/8 + 1/8 = 4/8 = 1/2
therefore the plant grew 0.5 or 1/2 in.
