Question

Andrew has six fewer coins than Casey. Bob has two more than twice as many coins as Andrew. Altogether, they have 544 coins. How many coins does Bob have?

Answer 1

Assuming: number of coins Andrew has=a, number of coins Bob has=b, number of coins Casey has=c
Andrew has six fewer coins than Casey, so, c-6=a, or a+6=c
Bob has two more than twice as many coins as Andrew, so 2a+2=b
Together, there are 544 coins: a+b+c=544. Rewrite the equation in terms of a: a+(2a+2)+(a+6)=544. Combine like terms: 4a+8=544. Solve the equation: 4a=536, so a=134. If b=2a+2, then b=2(134)+2=268+2=270.
Bob has 270 coins.