Question

Find the limit as x approaches 0 of x/sin3x

Answer 1

$\lim_{x \to 0} \frac{x}{sin 3x} = \\ =\frac{0}{0}= \\ = \lim_{x \to 0} \frac{3x}{3sin3x} =$
= 1/3  ( because the limit as x approaches 0 of  t/sin t = 1 ).