3.5x-10>-3 add 10 to both sides
3.5x>13 divide both sides by 3.5
x>26/7
x=(26/7, +oo)
...
8x-9<39 add 9 to both sides
8x<48 divide both sides by 8
x<6
x=(-oo,6)
Since this is a compound inequality with AND the solution set will be the union of the two intervals found above.
x=(26/7, 6)
Answer:
i don't know football but that's nice dude
There are 4 teams in total and each team has 7 members. One of the team will be the host team.
Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.
So total number of possible 9 member tournament committees will be equal to:

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

Therefore, there are 2917215 possible 9 member tournament committees
5x-2=3x+8
X=5
That's your answer