Find the perimeter of a quadrilateral with vertices at G (1, 6), H (2.5, 4), I (1, 2), K (-0.5, 4). Round your answer to the nea
rest hundredth when necessary. (5 points) 5 units 12.5 units 7.5 units 10 units
1 answer:
The points form a rhombus, so the total perimeter is 4 times the length of one side. The difference in coordinates G and H is ...
... H - G = (2.5-1, 4-6) = (1.5, -2)
Then the length of GH can be found from the Pythagorean theorem to be
... GH = √(1.5² + (-2)²) = √(2.25+4) = √6.25
... GH = 2.5
The perimeter is 4 times that, so is 4×2.5 = 10 units.
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Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is: