All categories

2 years ago

Richard and Teo have a combined age of 41. Richard is 11 years older than twice Teo's age. How old are Richard and Teo?

Mathematics

1 answer:

Stells [14]2 years ago

6 0

Richard = R & Teo = T

Richard & Teo are combined 41 it means R + T = 41

R = 8 + 2T

R + T = 41 #1

R = 8 + 2T #2

replace 2 in 1

8 + 2T + T = 41

8 + 3T = 41

3T = 41 -8 = 33

T = 11

R = 8 + 2*11 = 30

result = richard is 30 & teo is 11 years old.

2 times of Teo is 22

and 8 years older it means + 8

= 30

You might be interested in

Help me please thank you

TEA [102]

Answer:

about 41.14 pages per day

Step-by-step explanation:

She wants to read 576 pages in 14 days

Take the number of pages and divide by the number of days

576/14=41.14285714 pages per day

6 0

3 years ago

Read 2 more answers

Brainliest + points! <br><br> Please explain

Marina CMI [18]

Answer:

C. 14 feet

Step-by-step explanation:

Cos (60) = Adjacent / Hypotenuse

Cos (60) = 7/x

x = 7 / Cos(60)

x = 7 / 0.5

x = 14

7 0

3 years ago

Nancy leaves the school and drives toward her town at 27 mph. greg leaves the same school 2 hours later and drives the same rout

Paul [167]

Nancy's rate=27 mph
Greg's rate=45 mph
t=Greg's time
t+2=Nancy's time
Since they both traveled same distance then:
27(t+2)=45t
27t+54=45t
18t=54
t=3 hours
Greg will pass Nancy after 3 hours

6 0

3 years ago

Factor completely.<br><br> x2+3x−40<br><br><br><br> Enter your answer in the box.

Arlecino [84]

5x-40 if yo are trying to simplify it

7 0

3 years ago

A rectangle with a length of L and a width of W has a diagonal of 10 inches. Express the perimeter P of the rectangle as a funct

KatRina [158]

<h2>Answer:</h2>

The expression which represents the perimeter P of the rectangle as a function of L is:

$Perimeter=2(L+\sqrt{100-L^2})$

<h2>Step-by-step explanation:</h2>

The length and width of a rectangle are denoted by L and W respectively.

Also the diagonal of a rectangle is: 10 inches.

We know that the diagonal of a rectangle in terms of L and W are given by:

$10=\sqrt{L^2+W^2}$

( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )

Hence, we have:

$10^2=L^2+W^2\\\\i.e.\\\\W^2=100-L^2\\\\W=\pm \sqrt{100-L^2}$

But we know that width can't be negative. It has to be greater than 0.

Hence, we have:

$W=\sqrt{100-L^2}$

Now, we know that the Perimeter of a rectangle is given by:

$Perimeter=2(L+W)$

Here we have:

$Perimeter=2(L+\sqrt{100-L^2})$

7 0

3 years ago