<span>This gene sequence undergoes transcription to produce mrna by rna polymerase, and other proteins. This occurs in the nucleus of a eukaryotic cell. While prokaryotic cells lack the same type of nucleus that has organizational skills, the eukaryotic cell has this nucleus and contains various organelles for completion of this process.</span>
Answer:
50% of their children are likely to be carriers of cystic fibrosis
Explanation:
Since the normal allele "F" will be the dominant allele while the mutated CFR allele "f" will be the recessive allele, <u>the gene (pair of alleles) of the person that is a CFR carrier will be "Ff" while that of the normal person who isn't a carrier will be "FF"</u>. The attachment shows the crossing between the two parents. From the illustration in the attachment, for every 4 children given birth to, 2 of them will likely be normal, "FF", (not a carrier and doesn't have cystic fibrosis) while 2 others will likely be carriers of cystic fibrosis (Ff). Hence, 50% of their children are likely to be carriers of cystic fibrosis.
Answer:
Length of the cells = diameter of field of view/ number of cells across the field of view
Explanation:
therefore 2.25= 4.5*X
X= 2.25/4.5
=0.5 number of cells
Because at night there is no clouds in the sky to be cool but during the day there are clouds which give us cool air
Answer:
The answer is C.
Explanation:
There are dominant alleles present in three out of four (CC, Cc, Cc) and the recessive is always cc. Three out of four make 75% and one out of four is 25%. That makes 75% dominant and 25% recessive.
I hope this helps!