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Inessa05 [86]
3 years ago
6

Terrance is 3.5 years older than Stephanie. Stephanie is 22.5 years old. If the equation t – 3.5 = 22.5 models the situation, fi

nd the value for t, Terrance’s age.
Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
6 0
T= 3.5+22.5
T=26
Hope I helped!!
rosijanka [135]3 years ago
4 0
T - 3.5 = 22.5
t = 22.5 + 3.5
t = 26 <==
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Find an equation in standard form of the parabola passing through these points: (0,-6),(-1,-12),(3,0)
Elan Coil [88]
One form of the equation of a parabola is
y = ax² + bx + c

The curve passes through (0,-6), (-1,-12) and (3,0). Therefore
c = - 6                       (1)
a - b + c = -12            (2)
9a + 3b + c = 0         (3)

Substitute (1) into (2) and into (3).
a - b -6 = -12
a - b = -6                  (4)
9a + 3b - 6 = 0
9a + 3b = 6              (5)

Substitute a = b - 6 from (4) into (5).
9(b - 6) + 3b = 6
12b - 54 = 6
12b = 60
b = 5
a = b - 6 = -1

The equation is
y = -x² + 5x - 6 

Let us use completing the square to write the equation in standard form for a parabola.
y = -[x² - 5x] - 6
   = -[ (x - 2.5)² - 2.5²] - 6
   = -(x - 2.5)² + 6.25 - 6

y = -(x - 2.5)² + 0.25
This is the standdard form of the equation for the parabola.
The vertex us at (2.5, 0.25).
The axis of symmetry is x = 2.5
Because the leading coefficient is -1 (negative), the curve opens downward.
The graph is shown below.

Answer: y = -(x - 2.5)² + 0.25

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3 years ago
at wassamatta university, 55.7% of the student body are males. choose one student at random. what is the probability that the st
Nitella [24]
100% - 55.7%

= 100% - 55% - 0.70%

= 45% - 0.70%

= 44.30%

-----------

This means that the probability of selecting a female student at random is 44.3% as a percentage.
7 0
3 years ago
Read 2 more answers
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Answer:

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Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)
irina1246 [14]

Answer:

Maximize C =9x + 7y

8x + 10y \leq 17

11x + 12y\leq 25

and x ≥ 0, y ≥ 0

Plot the lines on graph

8x + 10y \leq 17

11x + 12y\leq 25

x\geq 0

y\geq 0

So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)

Substitute the points in  Maximize C

At  (0,1.7)

Maximize C =9(0) + 7(1.7)

Maximize C =11.9

At  (2.125,0)

Maximize C =9(2.125) + 7(0)

Maximize C =19.125

At   (0,0)

Maximize C =9(0) + 7(0)

Maximize C =0

So, Maximum value is attained at   (2.125,0)

So, the optimal value of x is 2.125

The optimal value of y is 0

The maximum value of the objective function is 19.125

4 0
3 years ago
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