Answer:
No, to be a function a relation must fulfill two requirements: existence and unicity.
Step-by-step explanation:
- Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
- Unicity is a condition that establish that each element of the domain of a relation must be related with <u>only one</u> element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.
Take the like terms on one side:
2m=6-14
2m = 8
m= 8/2
m= 4
Answer:
There is a 2/3 probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:
Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:
⇒ P (B2 / B1) = 2/3
Hence, there is a 2/3 probability that the other side is also black.
Answer:
208°
Step-by-step explanation:
Answer:
1. 0-9
2. 0-6
3. 0-6
Step-by-step explanation:
This scenario can be simulated by generating a set of three numbers using a number generator with numbers 0-9. The numbers 0-6 would represent couples who prefer indoor weddings. If all three numbers in the set are in the range 0-6, it would mean that all three couples prefer indoor weddings.
(ik you might not need this anymore, but I'm hoping it proves useful to others)
